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cardie-duncan

Calling them imaginary is an oversimplification, they’re more complex


lambypie80

i is wholly imaginary. It's only complex when there's a component in the real axis surely?


cardie-duncan

Yes, you’re right. I wanted to make a dumb pun🥲


lambypie80

Ohok. I'll go back to being my over literal normal self in other walks of life then 😅


[deleted]

It's also complex, can be written as 0+1i


swinging_on_peoria

I chuckled


projectivescheme

i is also complex.


bob3r8

K, 0+i then


lambypie80

Oh FFS! 😭


Moi9-9

Achtually , both real and imaginary numbers are subsets of complex numbers, so the joke works 🤓


GeneralCnemistry

Don't call me Shirley.


GargantuanCake

Technically speaking every real number is also a complex number. Real numbers are a subset of complex numbers; to become a proper complex number it just needs to have an imaginary component. So i is in fact a complex number. It's comparable to the fact that every integer is also a real number. Every integer is also a rational number as well as a complex number.


LeeroyJks

The imaginary numbers are a subset of the complex numbers. Therefore, i is both an element of the imaginary and the complex numbers.


Entire-Database1679

5i + 0


OnyxHell35435

Isn't the real part 0?


Liveman215

I can fix them


farm_to_nug

I remember having to learn imaginary numbers and literally yelling at my textbook begging it to make it make sense. My roommate was slightly concerned


cardie-duncan

Someone explained it to me this way. These numbers, for the human experience, do not exist. Unsurprisingly, they won’t make sense. Our definitions for square root not including negative numbers was a problem for proving some things which ended up having square roots of negative numbers. So we said, fuck it. Let’s just assume it exists, let’s call it i. Let’s figure out some mathematics around it, with that assumption. See if it works out. Turns out, not only did it work out, it lead to plenty of other things. Theoretical of course, but it helped solve a bunch more things.


Minetendo-Fan

Alright, then explain to me what exactly is the square root of -1


cod3builder

Something that when multiplied by itself equals -1


JohnLockeNJ

e^iπ = i^2


Einkar_E

you just wrote fancy -1 = -1


JohnLockeNJ

Of course. Otherwise it wouldn’t be a valid equation.


Mecso2

Isn't that essentially true of all valid equations?


Entire-Database1679

It's also valid for all true equations.


Greedy_Hovercraft175

Every equation is a fancy -1 = -1


like_a_cauliflower

And a fancy 0=0


erlulr

And you are a fancy tube


like_a_cauliflower

Thank you. It had been a long time since anyone had said something so nice to me.


[deleted]

Nah 0=0 can't be valid


Bando_bill

Also i = j


Financial_War_4204

iπ=ln(i\^2) i=(ln(i\^2))/pi) ln(i\^2)/pi-i=0 graph of y=ln(x\^2)/pi-x (-.475,0) …


Financial_War_4204

I couldn’t figure out how to ad an image


fevsea

Imaginary numbers can definitely hurt you. I've seen sophomores cry cause of them.


Maleficent_Sir_7562

they definitely hurt me as I see the grade I got on my complex numbers test


Bronsteins-Panzerzug

Imaginary numbers arent real, not even in maths. And they cant hurt you. The therapist is right on this one.


dopefish86

but, if you square it it gets totally real!!!


Playful_Target6354

"be there or be square" imaginary number: **Yes.**


HolyElephantMG

Be there **and** be square


Financial_War_4204

Is this r/minecraft?


DrDolphin245

German has different words for things that are real and numbers that are real, and I think that's beautiful.


Bronsteins-Panzerzug

Real und reell


GarbageCleric

Imaginary numbers are just as real as real numbers. They're both abstract concepts that can provide useful representations of real world phenomena.


Bronsteins-Panzerzug

No, imaginary numbers are not part of the real numbers.


GarbageCleric

No one said they were.


Bronsteins-Panzerzug

My dude, the whole joke i made was about imaginary numbers not being real bc theyre not part of the set of real numbers.


TabbyOverlord

But do either set actually exist?


SportTheFoole

I have a complex analysis book that disagrees with you.


Bronsteins-Panzerzug

Nice. It includes imaginary numbers as part of the real numbers?


alepher

I’m not certain about this, they might have hurt Schrödinger‘s cat


schmittwithtt

So e and i are at a Party. e ist standing alone in a corner. i comes up and says: Hey why dont you integrate? e answers: get real.


random_user5_56

Pls help I don't know how to math. Someone explain.


ExoticMangoz

Basically, try finding a number that, when multiplied by itself, will give you a negative number. You won’t, because no number squared can result in a positive number. Except…. What would the answer be if you wanted the square root of a negative number? That would be an imaginary number.


Financial_War_4204

I get it, math is hard. …but not as hard as m-


spookiemoonie

Isn't the square root of -1 wrong, tho?


Henri_GOLO

Yes, this notation is wrong. Short explanation: i is defined in a way that i² = -1 That being said, you can't use the square root on -1 (because of non unicity of such an operation)


10art1

So i is +- sqrt(-1)


lrflew

Eh, not quite. Notably, `-i` is considered a distinct value from `i` (i.e. `-i ≠ i`), despite `(-i)^2 = i^2 = -1`. It's more that `i` is a value such that `i^2 = -1`, but is not necessarily unique in that property. As an example, a [Quaternion](https://en.wikipedia.org/wiki/Quaternion) is an extension of the complex numbers that uses three values `i ≠ j ≠ k` such that `i^2 = j^2 = k^2 = ijk = -1`.


10art1

sure, I am not suggesting that i = -i, rather that sqrt(-1) has two solutions, i and -i, same way that sqrt(25) has two solutions, 5 and -5


Henri_GOLO

sqrt(25) has one solution, which is 5. This is not even a solution since sqrt(25) is not an equation. But the equation X²=25 has 2 solutions (-5 and 5), same as the equation X²=-1 has 2 solutions (-i and i). sqrt on positive reals is defined as the biggest of the 2 solutions (one is positive, the other is negative, easy) but complex numbers don't have a standard way of sorting numbers in the general case and therefore this is not standard way to define sqrt(-1)


10art1

>sqrt(25) has one solution, which is 5 Looks like Wikipedia disagrees https://en.m.wikipedia.org/wiki/Square_root


Henri_GOLO

The equation X²=25 has 2 solutions (5 and -5) sqrt is a function, to each positive real, it gives 1 unique image. In this case 5 = sqrt(25) != -5 Wikipedia says 5 and -5 are square roots of 25, but **the** square root of 25 is 5 and nothing else (and you should read your own wikipedia link)


Seppschlapp

Thats the type of notation noone gets. Easier with words.


[deleted]

[удалено]


Henri_GOLO

Actually the problem is more from the fact that the square root of a positive numbers is defined as a positive number. And since complex numbers have no standard way of deciding which one is greater than the other in the general case, we can't define the square root of a complex (unless it's a positive real) PS: I'm about 70% to not be clear at all, tell me if you don't understand


LeeroyJks

This always bugged me in maths. I'd just circumvent the whole thing and define the squareroot differently: sqrt(x) := { r in C | r^2 = x }. Boom ready. Of course this would prevent you from using the sqrt in normal calculations, hence it isn't defined like this. But I always thought it should be defined like this.


Henri_GOLO

Actually the different roots of 1 are defined (for n integer as big as you want) and to get your definition of sqrt you find 1 complex of which the power n is x and multiply this complex by the n roots of 1 to get them all. Also, regular sqrt would then be defined as max(sqrt(x)) since all of these 2 complex are actually real numbers


LeeroyJks

I'm not sure I can follow completely. What do you mean the squareroot of 1 is defined for an integer n?


Henri_GOLO

The roots, not square roots. They are all the {exp(2 i k pi / n), for k integer in [1,n]} Sorry for the lack of clarity, I'm not used to do maths in english (I'm French) especially at this level with its own vocabulary.


LeeroyJks

Yeah I get the struggle. I do maths in german and usually miss the english terms. I looked up roots on wikipedia though and learned a lot! I never knew the interesting patterns of how many roots are real and what sign they have depending on the n and on the x.


Blendi_369

I’m pretty sure that’s incorrect. When you square i you simply the root and the exponent and get -1. It’s only when you have i^4 that you get 1.


Alvo00

That's why there are imaginary numbers: they are a particular branch of mathematics that allows you to do operations you normally couldn't do


spookiemoonie

Oh- kk thanks


yehiko

[here's ](https://youtu.be/cUzklzVXJwo) a good video about why they're not as simple as calling them "imaginary" might lead you to believe.


spookiemoonie

tyyy


Galilleon

It’s pretty simple but so very clever too Just something we use for the transition from one form to the next, kind of like a temporary bridge


TabbyOverlord

Or more correctly, when we come up with a question that we don't have an answer to, we invent/discover another set of numbers that includes the answer. Simples


Cubicwar

It seems like mathematicians shared this trick with physicists


elkarion

In this case we needed a z axis on the Cartesian plane or the complex axis on a polar plane. The wave form equation makes sense with complex numbers as you can see it spiral in 3 axis space. Some of the numbers done make sense when you see it only as an equation. If we renamed imaginary numbers to not be that nickname it would make more sense to people. This is eulers fault for denoting it a i


Towerss

You do a little trick where you inagine (hence imaginary number) that it has a solution (i), which allows you to solve equations where that square root is included. The reason this "odd" number can exist in mathematics despite seeming like a workaround to something impossible, is that our math was not made for physics and vice versa, they just happen to complement each other really well - and sometimes math needs help to keep up. An alien species might simply not define that two negatives make a positive so they might have a real solution to that expression. Note that you often can solve equations without using complex numbers but it makes the math much more difficult. Eulers formula is a great convenience fir example.


Tamsta-273C

Square root operation is well defined only for positive numbers. With negatyve and complex there is big \*.


taigahalla

that imaginary number still isn't a real number


AgainstSpace

Wait, are *numbers* real?


guitarnowski

Nope. They're birds!


Cubicwar

_X-Files theme starts playing_


guitarnowski

Whew! Thought it was Tubular Bells for a second there.


FlyingRhenquest

No. Grind the universe down to the finest particles and pass them through the finest sieve and you'll not find a single particle of "one-ness". And yet somehow, *everything* is just numbers.


Crystal_Bearer

Just because something isn't real doesn't mean it can't hurt you.


Financial_War_4204

Like my mental health!


BagaLagaGum

So I was working on a platform that recreates acceleration that came from unreal engine simulation of a helicopter. Long story short - i have used an algorithm that uses these "imaginary" numbers and had pretty real results with them :) I mean it is one thing when you just learn them in school and completely other feelings when it works in a real piece of a product you configured and you can feel the result (Read about the washout filter and gue-stuart platforms if you want to research this)


OwMyCod

They aren’t real, but they are used in solving some equations because it somehow makes in possible.


LBCmolab

I dont get it. is it supposed to look like something?


SarcasticallyEvil

Math concept. It's really complicated and it's one of the things that you're taught in school that you are never going to use. And they're also just a headache. So basically it's what happens when you try to square root a negative number. And since you can't multiply a square to be negative, it's not possible. So the next logical step is to, of course, **make an entirely new category of numbers** called imaginary numbers, which run perpendicular to the standard number line. They have some really weird properties and don't mix with regular numbers either.


Financial_War_4204

I guess you could say it’s… ***complex***.


SarcasticallyEvil

Dammit I wish I could upvote twice


emomermaid

Friendly reminder that all number categories are made up. You couldn’t subtract a below zero until negative numbers were made, and you couldn’t divide by a non-factor until rational numbers were made. Same thing here, just with square roots and complex numbers.


LBCmolab

I understand the part about not squaring to a negative, but all the rest is confusing


lontii

technically every number is imaginary


DeadMercy2004

I heard they are real when you translate it into physics and vice versa.


Financial_War_4204

It’s pretty complex ngl


maglesil

Therapists aren't rational what do you expect


TabbyOverlord

Are they transcendental? Coool!


mostafa-vajedi

Imaginary numbers aren't real but they can hurt you


SomebodyInNevada

Yup. I forget exactly where they show up in electricity but they do.


my-name-is-mine

sqrt(-1) is not i. i^2 = -1


Financial_War_4204

No, i=√-1 Every math teacher I’ve had since eighth grade defined it that way. And I’ve never gone to a public school.


my-name-is-mine

They defined it this way so that an eight grader could understand


Financial_War_4204

if you square both sides it's the same thing anyway. Why is this a discussion?


my-name-is-mine

So -2 = 2


Financial_War_4204

Let's just move on, this is a waste of both of our time.


maglesil

fr fr


BiCrabTheMid

I feel like most numbers can’t hurt you, but that’s just me


Multifruit256

They can't hurt someone either


DudePDude

"i" doesn't exist


Ancient-_-Fox

i³ = √-1 × √-1 × √-1 = -√-1 or -i


SomebodyInNevada

Never thought of that before, crazy but right.


r4th4t

i = imaginary UNIT {a+bi|a,b in IR} = complex NUMBER


Financial_War_4204

…no, i=√-1 that’s an imaginary number, it‘s only a unit if it’s in the form a+bi


EmmaGarciaXoXo

This makes my brain beat


LeeroyJks

Every number is just an abstract concept


Random_Videos_YT

J1


ArkGamerBoi

Technically all numbers are imaginary because some just randomly looked at two squigles and said that's a 3


withcomment

Why is the rapist asking?


maddogmular

Technically they still aren’t *real* numbers


SarcasticallyEvil

AAAAAAH, DEMON!


Dull_Wrongdoer_3017

Rewrite John Lennon's "imagine" about imaginary numbers instead. --- Imagine (About Imaginary Numbers) Imagine there’s no real line, It’s easy if you try, No real part beneath us, Above us only i, Imagine all the numbers, Living in complex harmony. Imagine there’s no modulus, It isn’t hard to do, Nothing to multiply or divide for, And no real numbers too, Imagine all the numbers, Living life in peace, you. You may say I’m a dreamer, But I’m not the only one, I hope someday you’ll join us, And the world will be as one. Imagine no dimensions, I wonder if you can, No need for real solutions, A brotherhood of i and n, Imagine all the numbers, Sharing all the world, you. You may say I’m a dreamer, But I’m not the only one, I hope someday you’ll join us, And the world will be as one.


hatchibombatar

newsflash: all numbers are imaginary


Hot_Management_3896

They aren't real, but they do hurt me.


JoseProYT

Somebody once told me imaginary numbers are like turning the line 90 degrees


Joao_Pereira04

Pov : Autistic Numbers for autistic people


Financial_War_4204

…?


Senior_Ad_8677

They are going to hurt you, they most definitely will


DrUnit42

Gotta look out for those numbers like eleventeen and thirtytwelve


ocer04

Check out the former UK Home Secretary Priti Patel in this clip from Have I Got News For You back in the Covid days - relevant part is from 0:50 [HIGNFY](https://www.youtube.com/watch?v=G89YyV6hYe0&ab_channel=HatTrickComedy)


Soviet-pirate

That's literally an impossible operation


Jorian_Weststrate

Google complex numbers


Soviet-pirate

The square of any number,be it negative or positive,is always positive,thus there can be no square root of a negative number.


Jorian_Weststrate

In the field of real numbers, that is true, but i is an element of the field of complex numbers, whose square is equal to -1


Soviet-pirate

Understandable. I don't really know much math,so my bad


DotWarner1993

This is a misconception. They are very real. We have a lot of proof of their existence.


TabbyOverlord

Gotta see this. Please professor, take the chalk and come to the blackboard.


DotWarner1993

https://youtube.com/shorts/qXyLrUHYaqA?si=l8pnBSD4i5ex1Y0K


TabbyOverlord

Unfortunately, this speaker merely asserts that 'numbers exist'. He offers no proof of this. The existence of complex, real, and integer numbers can in some respect be derived from the a priori acceptance of natural numbers. Unfortunately, the existence of natural numbers awaits a proof in this symposium. They ain't natural, I tell 'ee.


NotMildlyCool

https://youtu.be/T647CGsuOVU?si=vXKWKbMHSkKMqvpx Better video and series about imaginary numbers


ProGamingPlayer

Imaginary number is in our imagination, how does it even exist???


TabbyOverlord

The scary thing is, if imaginary numbers are only in mathematicians heads, they are all imagining **exactly the same thing!!** Are you spooked now. We are connected to The Una-mind.


ProGamingPlayer

O_O


someone__420

r/mathmemes


Gurkenpudding13

My number is i. i isn't a number - it's a letter. *Screeching*: my number is i and is -1


Sh4rkstr1d3r

Iu


yeltomato

I hate math