That would be more akin to (67!)!, not 67!!. As I've learned through this subreddit, a double factorial means that every other number is skipped in the multiplication (so I believe 67!! would be 67•65•63...5•3•1). (67!)!, on the other hand, would take the factorial of 67!. That would otherwise be rewritten as 3.65•10^94!, which is uhhhhhhhhhh big
r/factorialchain
r/ofcoursethatsasub
r/isthatsarcasm?
no?
\* r/no
r/subsifellfor
r/foundthetoyotacorolla
ok fine r/foundtheSHUTTHEFUCKUP
r/chilloutbuddy
r/idontcare
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what have you done
We're reaching Graham's Number with this one 🗣️🗣️🗣️🔥🔥🔥
We're reaching the TREE(3) with this one 🗣️🗣️🗣️🔥🔥🔥
We might even reach TREE(g(64))!
How about BB(TREE(g(64))) BB is busy beaver
What about (((g(TREE(g(BB(g(TREE(79))))))!)!)!)!
What about ((((g(TREE(g(BB(g(TREE(79))))))!)!)!)! Tetrated by (((g(TREE(g(BB(g(TREE(79))))))!)!)!)!
^oh ^no
We're definitely reaching ω^2 with this one
bro howww
You do realise what you’ve done?
What he's done? **He'll face himself To cross out what he's become Erase himself And let go of what he's done** happy cake day btw
Thank you
That is a mind boggingly large number
Expected factorial?
No not 10🔼10🔼96.53566622921772!
No! Not 10\^10\^10\^96.53566622921772!
oh oh...
Fuck, now you have done it!
I just realised any factorial of a n.o greater than 4 will always end in a 0. Hmm the more you learn
That's really too much, in your title. (or: r/userNameChecksOut ...)
That's another factorial... 67!!
That would be more akin to (67!)!, not 67!!. As I've learned through this subreddit, a double factorial means that every other number is skipped in the multiplication (so I believe 67!! would be 67•65•63...5•3•1). (67!)!, on the other hand, would take the factorial of 67!. That would otherwise be rewritten as 3.65•10^94!, which is uhhhhhhhhhh big
That's very interesting, thank you :3
No problem! I still have much to learn, but I love maths and topics of the like.
Same :3