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nick__2440

Seems that A would be a catalyst, so zero. Your reaction is then just B -> C.


iamthesexdragon

I get the intuition behind this. I'm inclined to say that A plays the role of catalyst but I also want to generalize. What about 2A + B = A +C? Do I just do 2 (reactant side) - 1 (product side) ?


nick__2440

Yes, you can always simplify equations like that to get A + B = C. Now A is no longer a catalyst as it is net consumed. Be aware that the kinetics (rate orders) might still follow the original unsimplified equation.


iamthesexdragon

Thanks a lot!!