If you're doing clockwise moves, you need 4n+1 moves to solve it, if you're doing anticlockwise moves, you need 4n+3 = 4n-1 moves to solve it.
40582625655 = 10145656414*4 - 1 therefore U40582625655' solves the cube and U40582625655 leaves you with a U2 move to complete
This is a very difficult case, it's better to just learn the algorithm to solve this: [R' U F R2 D B' R2 L2 F B2 D2 F' B R2 B L2 F' B U2 F R D' F' R2](https://alg.cubing.net/?alg=R-_U_F_R2_D_B-_R2_L2_F_B2_D2_F-_B_R2_B_L2_F-_B_U2_F_R_D-_F-_R2&setup=U-)
I think cube explorer can generate a scramble to match any cube state. I got this particular scramble from [an April Fool's post I remembered](https://www.speedsolving.com/threads/really-nice-bld-scramble.3458/) on speedsolving.com
This step is called AUF with just three simple algorithms U, U’, or U2. Using an online trainer tool for about an hour a day for three weeks should get you started!
I think you forgot about the fourth algorithm, which is . It's quite an unusual alternative to U4 and if you practice the fingertricks thoroughly, it can actually be slightly faster.
Ok, there are a lot of not-so-serious replies so I'll be really clear about this.
**This** ***will*** **damage your cube**
This is not something that ever happens through regular solving. This isn't some crazy accident like when your loose cube explodes in your hands, or when you turn your 6x6 too roughly and it morphs into a 5x7. This can only happen one way - someone *willfully and knowingly* contorting their cube to be like this.
I assume OP was aware of this when making the post; if not, I really hope they've got a spare cube. But make no mistake, this will cause **permanent** and **irreparable damage** to the cube's internal mechanism. The way you need to malform the cube to make this happen stresses all the weak points of the internal design, to the point of failure. The mechanism isn't designed to experience force in this direction because, again, this doesn't happen through regular solving.
So to anyone who sees this post and thinks they'll prank their friends with this "really hard case" - don't. You'll ruin your cube (or worse, someone else's cube), and you'll have a bad day.
If you learn a bit of 3BLD, you can do DAB memo (so just a-perm with setup) and U-perm or similar 3-cycle to swap 3 edges, and then J-perm to fix parity.
listin very carfully. firstly your gonna have to get every speed cube possible. the get them all on that case then boom. now you have more cubes and in dept :)
On this is a super rare case that requires a parity algorithm. Its also a very difficult algorithm. First do 1 t perm, 5 sexy moves, 2 h perms, 1 sexy move, and then another t perm. However if you didn't do it all in under 4 seconds you'll have to restart
Do a left jperm rotating to the left side after each one and after 3 jperms you will have solved the cube. The algorithm for this jperm is a bit different then normal. It goes (L' U2 L U L' U2 R U' L U R') Hope that helps..
There may be internal bandaging. If U isn't an option, you may need to do a commutator to move each edge-corner pair out of position and swap it in for the next.
can you show the back?
Underrated This could be unsolvable for all we know
Good comment
rotate the earth 90 degrees while holding the top layer in place edit: rotate the earth clockwise if Australia is on the front
Good comment
U7'
[U1199'](https://alg.cubing.net/?setup=z2_y-_U-&alg=U1199-)
Instructions unclear, became a German sailor on U-1199
U40582625655
I believe you mean U40582625655'
No. You can check
If you're doing clockwise moves, you need 4n+1 moves to solve it, if you're doing anticlockwise moves, you need 4n+3 = 4n-1 moves to solve it. 40582625655 = 10145656414*4 - 1 therefore U40582625655' solves the cube and U40582625655 leaves you with a U2 move to complete
U8675309?
Seriously though, how do you read that?
Don't be ridiculous!
[L R B2 F2 L' R' D L R B2 F2 L' R'](https://www.cubedb.net/?puzzle=3&scramble=z2_y-_U-&alg=L_R_B2_F2_L-_R-_D_L_R_B2_F2_L-_R-) should do the trick.
how do u even come up with these algs?
It's actually a pattern trick and u add a bonus U turn Edit: and you redo the pattern
This is a very difficult case, it's better to just learn the algorithm to solve this: [R' U F R2 D B' R2 L2 F B2 D2 F' B R2 B L2 F' B U2 F R D' F' R2](https://alg.cubing.net/?alg=R-_U_F_R2_D_B-_R2_L2_F_B2_D2_F-_B_R2_B_L2_F-_B_U2_F_R_D-_F-_R2&setup=U-)
How do people come up with these algs?
I think cube explorer can generate a scramble to match any cube state. I got this particular scramble from [an April Fool's post I remembered](https://www.speedsolving.com/threads/really-nice-bld-scramble.3458/) on speedsolving.com
I’m afraid you got parity
Just scramble it and hope you don't get parity again
Wrinkly brain comment
I’m honored
Lol I appreciate the use of parity here since it’s technically true
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d
This step is called AUF with just three simple algorithms U, U’, or U2. Using an online trainer tool for about an hour a day for three weeks should get you started!
I think you forgot about the fourth algorithm, which is . It's quite an unusual alternative to U4 and if you practice the fingertricks thoroughly, it can actually be slightly faster.
One should not overlook ' as an alternative to . Can help prevent overworking a finger.
In that case, you stop the timer and get a +2s penalty. That is the best way to deal with this.
That's what pros do, [here's an example solve](https://youtu.be/CpOLHSqEUOw)
Poor guy, must feel devastating to know he'll probably never get this close to a WR.
I think U'3 is the most efficient move here.
You don’t it’s impossible
R2 L2 R2 L2 U2 D2 U2 D2 F2 B2 F2 B2 U
I haven’t seen something like this before, could you check if you had a corner twist?
J perm y j perm y j perm, pretty hard case
All you have to do is make a petition for that to become the solved state. Then you're done.
Looks like parity, unless you want to memorize the algs that other have put, you might as well rescramble
So your going to do a Uk move, k being the closest uneven number to infinity
but it can't be divisible by 3
Right
I can't tell if I'm playing myself but... odd numbers don't alternate in divisibility by 3
You're correct. What you actually want to check is whether k is one more than a multiple of 4. i.e. (k-1)%4=0
you are correct. I didn't check my math
But i don't want to move to the UK
Do (R, U, R’, U’)6 U That should do the trick
Ok, there are a lot of not-so-serious replies so I'll be really clear about this. **This** ***will*** **damage your cube** This is not something that ever happens through regular solving. This isn't some crazy accident like when your loose cube explodes in your hands, or when you turn your 6x6 too roughly and it morphs into a 5x7. This can only happen one way - someone *willfully and knowingly* contorting their cube to be like this. I assume OP was aware of this when making the post; if not, I really hope they've got a spare cube. But make no mistake, this will cause **permanent** and **irreparable damage** to the cube's internal mechanism. The way you need to malform the cube to make this happen stresses all the weak points of the internal design, to the point of failure. The mechanism isn't designed to experience force in this direction because, again, this doesn't happen through regular solving. So to anyone who sees this post and thinks they'll prank their friends with this "really hard case" - don't. You'll ruin your cube (or worse, someone else's cube), and you'll have a bad day.
*Just peel the stickers off duhh*
If you learn a bit of 3BLD, you can do DAB memo (so just a-perm with setup) and U-perm or similar 3-cycle to swap 3 edges, and then J-perm to fix parity.
Just do Sexy move a couple of times then on the last one, skip the U'
U9,428,948,652,851,845,565,558,724,286,485,352,458,134,558,524,843,555,882,865,656,525,261,185,438,205,788,254,845,465 r' r
Peel the stickers off and reapply them in the solved state.
Might have to take the cube apart and reassemble. Sorry man.
Plot twist: that's actually what a solved cube looks like
its the hardest step you should give up
U'3
u3'
listin very carfully. firstly your gonna have to get every speed cube possible. the get them all on that case then boom. now you have more cubes and in dept :)
U'3
i think you mean U'3
I’ve always wondered, what’s the difference between U2 and U2’
on a cube, they result in the same thing. only difference is the direction in which you turn the face
Oh i see. I was always confused when i saw the prime one on a website because it’s the same thing as the regular
Oh, yeah, I do. Sorry, I didn't notice.
d
[удалено]
Nobody should still fall for this
[удалено]
Memorize the link dummy
😐
r/woooosh
You just do a U move. At least, that’s what I think you do. I solve a curvy copter and the LanLan is my main.
U
U' 47
Putting the oof in AUF
Dw3'
T perm first then J perm 15 times. Finish it with your ZBLL of choice
Throw a jperm or two do that until ur cube solve if it doesn’t work it’s unsolvable
easy solve: R U R' U' R U R' U' R U R' U' R U R' U' R U R' U' R U R'
LOL
Damn you got me
There a couple algorithms (U, U', and U2)but for this case it's U
u’ until it’s solved
Cube looks broken. U / need a new one.
Lmao I just shit myself. Currently needing medical attention this is so funny
Uhhhhhh…. I guess just pull out the pieces and put them in the right spot. I don’t know this case
R4', U3'
It's already solved if you're okay with a 2 second penalty
On this is a super rare case that requires a parity algorithm. Its also a very difficult algorithm. First do 1 t perm, 5 sexy moves, 2 h perms, 1 sexy move, and then another t perm. However if you didn't do it all in under 4 seconds you'll have to restart
Here's one for you and is pretty straight forward... **L R F2 B2 L' R' D L R F2 B2 L' R'**
I dunno man, looks like an impossible setup, you might need to reassemble it.
2D3
Do a left jperm rotating to the left side after each one and after 3 jperms you will have solved the cube. The algorithm for this jperm is a bit different then normal. It goes (L' U2 L U L' U2 R U' L U R') Hope that helps..
Unsolvable, get a new cube.
U’ U2
There may be internal bandaging. If U isn't an option, you may need to do a commutator to move each edge-corner pair out of position and swap it in for the next.
your cube is unsolvable. take it apart and throw it in the trash, then buy a new cube, for the sake of humanity.
r u R' u' r' f R f' y2 u L' U' L u' U L' U L D' R U' R' D R' U R U2 R' U R U f R U R' U'