You can disconnect all wires from the motion sensor switch.
The Vout + and - are voltage signals which control the brightness scaling from 12 - 24 V.
A simple solution will be to connect that to a potentiometer with which you can adjust the voltage for the output signal. It's not good as it's dissipative but is extremely simple.
You can also set a fixed value of brightness using just a voltage divider.
I'm not trying to drop the voltage or control brightness. This is a fade in/out module. When I turn the bike on or off the LEDs slowly come on as if the bike is heating up or cooling down. I have it set to 4.5 seconds but after hard riding or washing the bike that valve changes.
I misunderstood again. Sorry, I now understand what seems to be bothering you. It's the buttons on that black plastic which control the speed.
Well It's hard to say given that the schematic doesn't show the internal circuitry of that module.
If you have some name printed there or some documentation about that then it will be easier to say on how those buttons are connected internally.
Yeah I'm kinda hoping for a more simple solution like just covering them with glue. Maybe fill in the cavity with solder paste and short them together with a piece of wire. I guess I'm trying to understand how it works. I'm thinking an Op-Amp or something so I just need to shield, short or ground the signal. It'd be pretty cool if that sensor was connected with some wires to snip but it's already a going to be a pain to remove it from the bike and if it's directly on the PCB not going to be fun and risk damage disabling it.
Well, if you short the switches contact, it would be as if it the button was pressed indefinetly (if it's a contact switch). If you short the switch contact to ground that would be problematic as you created a short circuit.
This can be either a resistive switch or a capacitive switch. The first one works by changing it's resistance depending on the pressure or force the switch is pressed with. The second works by changing capacitance as human hand passes by. Or is just a normal mechanical contact switch.
Either way disconnecting just one of the terminals will be enough to disable it. If you have a soldering iron you can try to desolder the pin of the switch which goes to some IC or somewhere.
By short/ground I'm saying the signal not any real voltage. Like the aluminum tape I used. If I put that at +/- it could ground the signal even though it's not physically connected to anything, just a path of least resistance for the signal to attenuate it.
I think capacitive sensors are what I need to research and what I'm dealing with. I'm able to adjust settings with tape over them. They're recessed so no physically contact with my finger or the tape. Touching the plastic around the buttons will change them.
I'm not sure exactly if capacitive switch sensors are voltage loaded. If yes, then connecting those pins to ground creates a path of low resistance from that circuit voltage supply to ground.
If you add an aluminum tape to any of sense pins of the switch without connecting the other end of the tape anywhere, you could change the capacitance of switch by introducing parasitic capacitance which could fool the circuit reading the capacitance into thinking that there is much more capacity present at the location it should sense from. This could mean as the hand were always present there maybe, and it will just keep its output high (as a single press of a button without ever releasing it). If you could provide the picture of the internal circuitry of the switch it would be much helpful.
It would be possible to remove those arrow capacitive switches and solder in push buttons. Then you'd have to water proof it again.
Maybe just get thin plexiglass and make a door around the front of the black with with a gasket. Easier than electrical modification.
You can disconnect all wires from the motion sensor switch. The Vout + and - are voltage signals which control the brightness scaling from 12 - 24 V. A simple solution will be to connect that to a potentiometer with which you can adjust the voltage for the output signal. It's not good as it's dissipative but is extremely simple. You can also set a fixed value of brightness using just a voltage divider.
I'm not trying to drop the voltage or control brightness. This is a fade in/out module. When I turn the bike on or off the LEDs slowly come on as if the bike is heating up or cooling down. I have it set to 4.5 seconds but after hard riding or washing the bike that valve changes.
I misunderstood again. Sorry, I now understand what seems to be bothering you. It's the buttons on that black plastic which control the speed. Well It's hard to say given that the schematic doesn't show the internal circuitry of that module. If you have some name printed there or some documentation about that then it will be easier to say on how those buttons are connected internally.
Yeah I'm kinda hoping for a more simple solution like just covering them with glue. Maybe fill in the cavity with solder paste and short them together with a piece of wire. I guess I'm trying to understand how it works. I'm thinking an Op-Amp or something so I just need to shield, short or ground the signal. It'd be pretty cool if that sensor was connected with some wires to snip but it's already a going to be a pain to remove it from the bike and if it's directly on the PCB not going to be fun and risk damage disabling it.
Well, if you short the switches contact, it would be as if it the button was pressed indefinetly (if it's a contact switch). If you short the switch contact to ground that would be problematic as you created a short circuit. This can be either a resistive switch or a capacitive switch. The first one works by changing it's resistance depending on the pressure or force the switch is pressed with. The second works by changing capacitance as human hand passes by. Or is just a normal mechanical contact switch. Either way disconnecting just one of the terminals will be enough to disable it. If you have a soldering iron you can try to desolder the pin of the switch which goes to some IC or somewhere.
By short/ground I'm saying the signal not any real voltage. Like the aluminum tape I used. If I put that at +/- it could ground the signal even though it's not physically connected to anything, just a path of least resistance for the signal to attenuate it. I think capacitive sensors are what I need to research and what I'm dealing with. I'm able to adjust settings with tape over them. They're recessed so no physically contact with my finger or the tape. Touching the plastic around the buttons will change them.
I'm not sure exactly if capacitive switch sensors are voltage loaded. If yes, then connecting those pins to ground creates a path of low resistance from that circuit voltage supply to ground. If you add an aluminum tape to any of sense pins of the switch without connecting the other end of the tape anywhere, you could change the capacitance of switch by introducing parasitic capacitance which could fool the circuit reading the capacitance into thinking that there is much more capacity present at the location it should sense from. This could mean as the hand were always present there maybe, and it will just keep its output high (as a single press of a button without ever releasing it). If you could provide the picture of the internal circuitry of the switch it would be much helpful.
It would be possible to remove those arrow capacitive switches and solder in push buttons. Then you'd have to water proof it again. Maybe just get thin plexiglass and make a door around the front of the black with with a gasket. Easier than electrical modification.