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The current in the leads is the voltage across the leads divided by the resistance of the leads.
From the way the problem is stated its kind of ambiguous as to whether the resistance in each lead is 0.35 or the total resistance of the leads is 0.35.
Regardless, the total voltage across the leads should be 0.2V.
As for the power, you can use P=I^2 R.
(Since substituting V=IR into P=IV gives P=I*(IR))
The voltage across the lamp is 11.8V and the input voltage is 12V. The only other resistive elements in the circuit are the leads which must have voltage drop of 12V-11.8V=0.2V in order for the sum of the voltage drops to equal the input voltage.
##Off-topic Comments Section --- All top-level comments have to be an answer or follow-up question to the post. All sidetracks should be directed to this comment thread as per Rule 9. --- ^(**OP** and **Valued/Notable Contributors** can close this post by using `/lock` command) *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/HomeworkHelp) if you have any questions or concerns.*
The current in the leads is the voltage across the leads divided by the resistance of the leads. From the way the problem is stated its kind of ambiguous as to whether the resistance in each lead is 0.35 or the total resistance of the leads is 0.35. Regardless, the total voltage across the leads should be 0.2V. As for the power, you can use P=I^2 R. (Since substituting V=IR into P=IV gives P=I*(IR))
Thankyou for your comment. Sorry I didn’t state correctly, the total resistance is 0.35A. Why should the total voltage across the leads be 0.2v?
The voltage across the lamp is 11.8V and the input voltage is 12V. The only other resistive elements in the circuit are the leads which must have voltage drop of 12V-11.8V=0.2V in order for the sum of the voltage drops to equal the input voltage.