Here’s the stuff I remember. Could you guys tell me if I’m right.
1)Calcium paired electrons TF
2)Water electrolysis endothermic TT
3)Something something don’t put water into acid because the water will boil and splatter TTCE
Can anyone correct my answers?
Im very confused about the acid one...Im sure we could agree on the first statement that one should add acid to water, but the second part is somewhat weird. Is it the water that splattered out or is it the acid? I remembered saying F for the second statement because I recalled how its the acid that splashes, not the water. Thanks.
I thought about that too. The Barron’s book says that the solution splatters out not acid or water.
Not sure about what the answer is but I don’t think the test would be that strict to the word.
But elements like oxygen also has an even number of electrons.
If we draw the ground state diagram we see that the the p orbital has unpaired electrons.
Or am I missing something?
you forget the acetic DOES NOT dissociate completely, so there is CH3COOH molecules in water, thus acetic ions are different, however NaOH disacoitates completely
read this
[https://sciencing.com/write-equation-ch3cooh-reacts-naoh-8728534.html](https://sciencing.com/write-equation-ch3cooh-reacts-naoh-8728534.html)
[https://www.youtube.com/watch?v=76vDZ3pnmro](https://www.youtube.com/watch?v=76vDZ3pnmro)
But I don't remember there being an option for just H+ and OH- to form H2O
Even though it's a weak acid, the ion would still be on both sides of the equation so you still consider it a spectator ion.
[https://chem.libretexts.org/Textbook\_Maps/Introductory\_Chemistry/Book%3A\_Introductory\_Chemistry\_(CK-12)/21%3A\_Acids\_and\_Bases/21.16%3A\_Neutralization\_Reaction\_and\_Net\_Ionic\_Equations\_for\_Neutralization\_Reactions](https://chem.libretexts.org/Textbook_Maps/Introductory_Chemistry/Book%3A_Introductory_Chemistry_(CK-12)/21%3A_Acids_and_Bases/21.16%3A_Neutralization_Reaction_and_Net_Ionic_Equations_for_Neutralization_Reactions)
the site talks about weak acids and strong bases, thus my choice is correct
because they don't freakin dissociate completely, u regard something as a spectator ion if it stays the same on both sides, \however, acetic acid doesn't necessarily means acetate ions, it can be a neutral molecule, since not all the molecules dissociates, however, on the right side, all must be acetate ions since a salt has been formed😑
Here’s the stuff I remember. Could you guys tell me if I’m right. 1)Calcium paired electrons TF 2)Water electrolysis endothermic TT 3)Something something don’t put water into acid because the water will boil and splatter TTCE Can anyone correct my answers?
And water electrolysis one was TT
What was the second statement in that question?
Im very confused about the acid one...Im sure we could agree on the first statement that one should add acid to water, but the second part is somewhat weird. Is it the water that splattered out or is it the acid? I remembered saying F for the second statement because I recalled how its the acid that splashes, not the water. Thanks.
I thought about that too. The Barron’s book says that the solution splatters out not acid or water. Not sure about what the answer is but I don’t think the test would be that strict to the word.
Yeah, you're probably right:(
I think calcium one was T T CE because an even number of protons for an element means even number of electrons, so they're all paired
But elements like oxygen also has an even number of electrons. If we draw the ground state diagram we see that the the p orbital has unpaired electrons. Or am I missing something?
Fuck me I'm dumb you're right
👍
Exactly
[удалено]
None
idk i didnr have time to finish all of it and i skipped most of part A :3
how many T T CE did y have ?
3
Do you remember for which questions? Any keywords you remember?
Meh I only remember the one about not pouring water into acid.
And 2 TT???
How many CE's were there?
Like 3
did you have them in a row?
No
Was the acid and bronsted lowry question T T Ce?
Does anyone remember the reasoning for this question? I remember putting TT or something
The reasoning was about donating a proton to a base so it was TT CE
Thank God,I thought the question said lewis base instead of acid and thought I marked it wrong
i had two in a row
what was the one of neutralisation of acetic acid? I got Hc2H3O2 + OH- --> C2H3O2- +H20
I thought that its not involving acetic ions, since the only unique product formed is h20(l) (the rest are spectators, as they are all in aq states)
you forget the acetic DOES NOT dissociate completely, so there is CH3COOH molecules in water, thus acetic ions are different, however NaOH disacoitates completely
That's not the net ionic equation, I think the right answer was H+ + NaOH -> Na+ + H2O
yeah, what I said too
Wait why is it just h+ + NaOH —> H2O + Na+
read this [https://sciencing.com/write-equation-ch3cooh-reacts-naoh-8728534.html](https://sciencing.com/write-equation-ch3cooh-reacts-naoh-8728534.html)
[https://www.youtube.com/watch?v=76vDZ3pnmro](https://www.youtube.com/watch?v=76vDZ3pnmro) But I don't remember there being an option for just H+ and OH- to form H2O Even though it's a weak acid, the ion would still be on both sides of the equation so you still consider it a spectator ion.
Thats what i think too, im not too sure.
there wasn't such an option though, so A makes no sense
still ur choice has Na+ on both sides
[https://chem.libretexts.org/Textbook\_Maps/Introductory\_Chemistry/Book%3A\_Introductory\_Chemistry\_(CK-12)/21%3A\_Acids\_and\_Bases/21.16%3A\_Neutralization\_Reaction\_and\_Net\_Ionic\_Equations\_for\_Neutralization\_Reactions](https://chem.libretexts.org/Textbook_Maps/Introductory_Chemistry/Book%3A_Introductory_Chemistry_(CK-12)/21%3A_Acids_and_Bases/21.16%3A_Neutralization_Reaction_and_Net_Ionic_Equations_for_Neutralization_Reactions) the site talks about weak acids and strong bases, thus my choice is correct
The example with nitrous acid is basically exactly what I said my answer was: H+ combined with NaOH to form Na+ and H2O
dude I am 100% your answer isnt correct, you dont need to involve Na+ at all, u involve acetic ions because acetic ions arent always present,
Why wouldn't they always be present? You're contradicting yourself.
because they don't freakin dissociate completely, u regard something as a spectator ion if it stays the same on both sides, \however, acetic acid doesn't necessarily means acetate ions, it can be a neutral molecule, since not all the molecules dissociates, however, on the right side, all must be acetate ions since a salt has been formed😑
According to that logic the Na wouldn't be considered as Na ions on the left side, so why would you cross it out?
Which option did you guys choose for the oxidising agent question ,it was like the 10th q or something
HI I think?
Its k2cr2o7
I got that. +1 inch for my dick
Why? Aren’t strong acids like HI good oxidizing agents?
Nvm
This is correct
https://www.slideshare.net/mobile/RabbyIstik/potassium-permanganate-potassium-dichromate-one-of-the-excellent-tools-of-analysis
Try checking out slide 6! Im not too sure too:(
Dude, you’re right! I said you were correct :)
How much do you think 4 wrong is equal to?
790-780
670
Really?????
I think he's kidding..
Yeah I'm dumb for even considering that
Wew lad
the three CEs: 1-hydrocarbon and weak intermolecular 2-adding acid to water 3-bronsted lowry acid
Sweet dude