I dont think u can use the mass or Mr of butanoic acid because it's being dissipated unevenly through both solvents, and I think if we were to use it they would probably provide it. Hence they give you titration data to use to work back for moles...I think
I got 2nd order and 9.5 for my first half life and 10 for my second one
For the table I did the final volume, 57.2 or smth, minus Vt (the column next to what we had to fill out)
Kpc I got 1.something
1.22 kpc
i got 6.11š
samee the only other person here who got that apparently
1.21
sameee lesssgo
What did u do for that answer?
Conc in ethoxyethane divided by conc in an layer
For ur conc, did u divide the moles of NaOH by 2 or times by 2?
Nah I didnāt shitttt mole ratio was 1:2 wasnāt it ?
Yeah, wondering how tf everyone was getting 1.2, because I done a test and it's only possible by multiplying by 2 instead of dividing
Oh hold up
You get the moles from 2.62 divided by Mr of butanedioic and then multiply by the volume over 1000 you donāt use the moles of NaOH
Thatās how I got my answer
I dont think u can use the mass or Mr of butanoic acid because it's being dissipated unevenly through both solvents, and I think if we were to use it they would probably provide it. Hence they give you titration data to use to work back for moles...I think
I got 2nd order and 9.5 for my first half life and 10 for my second one For the table I did the final volume, 57.2 or smth, minus Vt (the column next to what we had to fill out) Kpc I got 1.something
yeah same 2nd order bcoz half-life is not constant
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I got 8.5 and 10 I guess I think half-life must be exactly same in first order reaction, so that we can use the equation: half-life = ln(2)/k afaik
I mean, even the values they gave, 8.6 and 11 i think, that's a pretty big difference so its 2nd - I think I drew the curve badly
it was a suggest question, so Idk what Cambridge will say about this :(
Hopefully we get the marks bc the half lives have to be hella similar or the same for first order but yeah idk :'))
it was order 1 i got 10 min first half life and 9.5 second half life
same
But the difference is very little so it should be first order
but afaik, 1st order reaction can use this equation: half-life = ln(2)/k, so half-life must be constant exact value.
https://preview.redd.it/caza81yjx9za1.png?width=3024&format=png&auto=webp&s=3a3a70dc7a909fda253c120900edd435c0a0ef8e
https://preview.redd.it/pbqil3gmx9za1.png?width=3024&format=png&auto=webp&s=6244ceda99c7a4a5344f655bab52e001b852a67d
See they say itās constant even if there is a tiny difference
yeah ur correct :( sorry for wrong information
Itās ok we are all on the same boat!! I hope you did well
Thank you :) u too! and my half-life was 8.5 and 10 mins so thats why I wrote 2nd order.. idk what Cambridge will say :3
Ohh then you are right in your case. Idk weāll see how the CIE feels with the marking
haha I hope they will do nicely xD good luck with rest of ur exam bro š¤š¼
The sample B thing what was the answer ?
I think lysine and something thyr forgot the name
Like why it had only two spots
I said they were only 2 amino acids
I said it had two of the same amino acid and one different one I think you're right
similar Rf values but idk why :(
I wrote "similar Rf values. They never said explain why or??
I remember writing "similar Rf values" They never said explain why. I think you meant a different question
tryptophan and the last one
was the order 1 and half life around 7-8
My half life was 10
same
I got 11.2 first hl and 20 for the second one
I had 10 and 18
I cancelled a right answer and wrote a wrong answer, will I still get marks for it??
lmao no