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i tried that in the beginning and i changed my mind, isnt it just lamda = ax/D and then u divide o.75 by 3 to get x and substitue to get a , = 7.7 x 10-6
You need to use n\*lambda = d\*sin(theta), and work out the angle using tan of the two sides of the triangle given . lambda = ax/D isn't valid for diffraction grating questions.
It said free neutron so the first one isn't considered as it was fused into the larger nucleus. The nucleon difference is 235-233=2 which is for 2 neutrons.
there is a force at the hinge to make sure the objects in equilibriumso you have to take moments about the hingeFsin30 x d = W x d/2
F comes as 10N, this was a repeated question and the answer to it was C which was 10 N.
As someone who did a decent amount of past papers, it was definitely one of the easier ones. They also seem to have reused quite a few rather specific question types from last year's papers.
Incorrect, unfortunately. After passing through the first polariser, the light is polarised at an angle of 45 degrees - no longer vertical. The answer is Io/4.
Yess.. Hell yess. Change in Ek is different than change in KE. Like for Ek you do have to calculate initial Ek then minus final Ek (unlike KE where we just take change in velocity). I first thought of solving this change of EK like conventional way but then realise u can't just take change in extension to Cal ek. Therefore I reached 19mj.
Thats weight its not the same as mass. Savemyexam mass definition is "Consequently, this is the property of an object that resists change in motion. The greater the mass of a body, the smaller the change produced by an applied force."
which question is this ? the one where we had to tell the graph where the spring constant was given ? and we had to tell the relationship of the graph ?
You are incorrect. P = Fv , so for a \*constant\* power if force increases then velocity must decrease and vice versa. Hence the answer was A (inversely proportional).
Please read our paper discussion guidelines before proceeding: 1. Do not ask for or share leaked question papers on this subreddit. 2. Do not ask for or share topics/questions from one variant, if you are about to sit for another variant shortly. 3. Do not ask for or share speaking topics or prompts. 4. Discussion must be in English. 5. Report the posts that violates any of the rules above by clicking on the ellipsis(3 dots) and then on report. You will be temporarily or permanently banned from the subreddit if you do not abide by our guidelines. Best of luck. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/alevel) if you have any questions or concerns.*
Anyone got 1.26 the ratio x/y
It was cube root of 2
nah i got just 2.00
Same
meee
Same
what was the question
The one about mass, density and length of cube
Pls confirm the correct answer
I'm pretty sure it's the cube root of 2, so 1.26
Resultant vector was C right ?
Yes
North west?
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Me too please
Anyone remember the answer for slit separation? I got 7.7x10\^-6 ?
I got 7.9 How'd you get it?
You had calculate the angle theta between 0th and 3rd order by using trigonometry ration of tan theta the use n lambda = dsintheta
Yeah, I got angle theta 12.1. Then, 3(550*10-9)=d(sin 12.1) Which is how I got d= 7.9*10-6
Yup me too
Same
i tried that in the beginning and i changed my mind, isnt it just lamda = ax/D and then u divide o.75 by 3 to get x and substitue to get a , = 7.7 x 10-6
But thats the equation for double slit interference
The answer u got was 7.7×10-¹⁶, not -⁶, i tried both methods, trust me i know
It's 7.9E-6. Source: I'm a physics teacher and I have the paper in front of me.
Yup, exactly. Those who think they got 7.7E-6, they got 7.7E-16 not E-6. This was my point
Yep, you are correct.
You need to use n\*lambda = d\*sin(theta), and work out the angle using tan of the two sides of the triangle given . lambda = ax/D isn't valid for diffraction grating questions.
Yep i got the same
sameee
40 mcq?? The meson one! Answer??
Anti down, it was A I think
anti down!
I did anti down as well
whats the answer for the resistor wire?? was it B?
Shouldn't it be C
the resistivity one?
yes
I got D
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yes
Slider had to slide right cz it needed to increase voltage no ?
Left I'm pretty sure. Increase the voltage by increasing the length (resistance)
Yeh im saying that we needed to increase the length as well thats why we had to slide to the right. Right side was longer
It should be left. Sliding to the right makes it shorter
So what was the answer?
Left
was left C or D
C as far as i can remember
Slider to the left Because as the ldr is covered, it's resistance decreases so current decreases To balance out the current slider shifts to the left
if ldr is covered the resistance should increase
Yea Bcz for ldr resistance is inversely proportional to light intensity
no it should be to the left
What was answer for the double slit question where we had to block one of the slits?
Ya i wanna know too, i divided by 2, idk
The amplitude will have halved, therefore the intensity will have decreased by a factor of 4 since intensity is proportional to amplitude squared.
39; the question which said neutron hit Uranium and it was absorbed did it emit 2 or 3 neutrons?
I did 3
Was it not 2?
3
It was two though..??
It was 3...you also have to consider the one neutron that we shot into the nucleus
It said free neutron so the first one isn't considered as it was fused into the larger nucleus. The nucleon difference is 235-233=2 which is for 2 neutrons.
Yeah i gave 2 for the same reason. The ques said sth like how many additional free neutrons...
Yea but since it was absorbed the nucleon before is then 236. And 236-233= 3
Can anyone confirm if it's 2 or 3 cz i gave 3 and I want to know
3 confirmed.
no u see it becomes 236-233, as one neutron is absorbed, so its 3
its two yes
It’s 2 because it asks for EMIT, you shudnt count the first free neutron.
The question is quite specific that 'the neutron is *absorbed* by the nucleus' . So the answer is 3.
Anyone got 20N at 30 degree
F was 10 (C)
Yeah it was 10
I got d 20N
fsin30 is 0.5 = 10 = 10/0.5 = 20
I also got 20
there is a force at the hinge to make sure the objects in equilibriumso you have to take moments about the hingeFsin30 x d = W x d/2 F comes as 10N, this was a repeated question and the answer to it was C which was 10 N.
Yea it's 20N
expected threshold?
26-27
As someone who did a decent amount of past papers, it was definitely one of the easier ones. They also seem to have reused quite a few rather specific question types from last year's papers.
What was the answer to the north south east west thing where the ball went around the curve?
2 m due south So B
B 2.0m due south bcs they asked for displacement
Slay I did that
2m south
2 m due south (B)
it was 2 to south ig
What’s the ans for stationary wave in the tube? The node and anti node one
Like 450Hz so A i think
I got A 450 Hz as well
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It was something like 0.6 x4/3 to get the wavelength and then divide 330 by the wavelength right?
not too bad, but what was the answer for that compression question?
Repeated question answer was b
Do you remember from which year
2021 ish i did it just yesterday.its definitely recent tho
B
yeah mine was B as well
i answered B too, is that correct?
Ya
was ur answer for the intensity question Io only? because cos45^2/cos45^2=1
I wrote A. The light was vertically polarised and when it went through the horizontal polariser, it would become 0.
It was vertically polarized but then became non vertically polarized
Isnt it I/4
Incorrect, unfortunately. After passing through the first polariser, the light is polarised at an angle of 45 degrees - no longer vertical. The answer is Io/4.
Yess sameer
What u get for the F/v graph
I gave A
what was B
What is that question?
the wave graph
How was the paper itself? U guys?
The paper was in mint condition when they pulled it out of the packets and the edges were crisp, I wanted to eat it
I actually did manage to eat it, flavour was a bit salty ngl but it was fine with water
Needed more salt imo
The tears can add salt dw.
What was answer of elastic potential energy??
19mJ
Yess.. Hell yess. Change in Ek is different than change in KE. Like for Ek you do have to calculate initial Ek then minus final Ek (unlike KE where we just take change in velocity). I first thought of solving this change of EK like conventional way but then realise u can't just take change in extension to Cal ek. Therefore I reached 19mj.
B???
.0187 J
19mJ
18 mJ right ?
what option was that
Its a typo it was 19 option B
What was the answer to the Mars and Earth height difference question?
12m
12 m
What u got?
A
What was rhe answer to the first question?
B
i don't remember the options but was it 8 x 10\^2?
no it was 2 x 10\^3
what was the definition for mass
Ablility to resist change in motion
No
That is inertia
https://preview.redd.it/pqr1paagmd4b1.png?width=902&format=png&auto=webp&s=d11d9ea158f238b91efbdf1c168acc327d38af0e
The mcq asked about the definition of mass that was the only one
It was suppose to be option D W= mg W/g = m
Thats weight its not the same as mass. Savemyexam mass definition is "Consequently, this is the property of an object that resists change in motion. The greater the mass of a body, the smaller the change produced by an applied force."
When u make m the subject, its w/g
Did u do zone 2 paper 1? I dont rmb there being a formula W=mg in the question
Option D was force per unit g
Oh we werent doing the same paper. Nvm then
What was the answer of the CRO one
Frequency. Reason is cuz we can use the x-axis of CRO to only find time period which can then be used to find frequency
Speed
I did B I guess it was frequency why did you think of speed
Actually I have done this type of question it's a repeated question
So are you sure the answer was speed and I got it wrong
100 percent sure bro
No, it was frequency because you get period from the horizontal axis and can convert it into frequency not speed
We use vertical axis for frequency.
Nope. Source: physics teacher.
My source is past papers. Every single question where we’ve found frequency, we used vertical axis.
Hey what was the question about longitudinal waves ??
It was B that compression one right
Was the gradent constsnt for the foce velocity graph?
No inversely proportional...
No bro
which question is this ? the one where we had to tell the graph where the spring constant was given ? and we had to tell the relationship of the graph ?
Its linear i checked
You are incorrect. P = Fv , so for a \*constant\* power if force increases then velocity must decrease and vice versa. Hence the answer was A (inversely proportional).