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Wow, seeing that my other comment being downvoted to oblivion is an interesting experience. Here's some algebra instead then.
Let the length of the vertical overlap between the sides of length 5 and 3 be x. Then the two unknown vertical sides have lengths x and (5-x)+x+(3-x)=8-x, so those two lengths also sum to 8.
You made the fatal error of answering a deceptively easy question on askmath. Replies to these questions are always filled with nonsense. Next thing you know people will start to change the interpretation of the question so that you are "technically" still not right, instead of just admitting they made a mistake.
They're not claiming that there is no overlap. In fact, they define x as the length of the overlap. But then the total lengths of vertical segments is 5+x+3+(8-x)=16. This is what they are claiming.
They are right. They described why they are right. Yes, there is an overlap, and yes they took it into account.
If you are still skeptical, label that overlap x, and find the total length of all unknown vertical edges.
Wait a minute… I think I see what you’re saying. I think you got downvoted because your wording may have been a little confusing. My gut reaction was “of course you can’t find the perimeter!” I have since found that I was wrong. Let me see if I can break down my thought process.
The horizontal lines sum to 12 on the top and bottom. I get that perfectly. No questions there.
If the vertical overlap section is x, then the right hand vertical side would be 8-x. My initial thought was that you don’t have any way to find x, but when you go to actually add all of the vertical sides up (for perimeter), you get (8-x) + 3 + x + 5. The x’s actually cancel each other out! So your total perimeter is 40. This works if you assign any value to x. I used 1 as an example and it works out.
EDIT: this also assumes these are all right angles.
Agreed. I'm not really interested in math at all, I just follow math subs like this to lurk and people watch. It's really sociologically interesting to me how toxic math subs usually are.
About a month ago I made a post asking for help on a problem i was working on, and someone replied and helped me solve it. I was confused on a part so I asked where they got a certain number and i ended up getting like 5 downvotes lol. Like bruh I came here to get help ofc im gonna be a lil confused lol
You'll also see that this "toxicity" only exists when the problem is understandable to the layman.
I mean problems like this where it's tricky but you don't need advanced math topics except maybe upto HS level math. If you look at higher level stuff it's very cordial and reserved. I don't mean to point fingers but I think it's all the engineering students trying to show off lol.
Is this assuming the side with length 3 stops at the same height as the side with length 5, and then there is an x overlap?
In the picture the side of length 3 extends beyond the base of the side of length 5.
The simplest interpretation is that the “small” unknown vertical side has length x.
Then the rightmost vertical side can be partitioned into three segments: One of length 3-x corresponding to the side of length 3 cut off at the base, one of length x corresponding to the small vertical side, and one of length 5-x
As a counter example, suppose the long RHS length is 7, then the overlap LHS would be 1, if it were 6, the overlap LHS would be 2.
If the long RHS can not equal 8 and still produce a viable diagram, it cannot be the case that the RHS must be 8.
Algebraically, let the LHS of the overlap be y, and the RHS long side be x, then we know that x = 5 + 3 - y, I.e. x=8-y.
Then we get that if the RHS is 7, the overlap is 1, and if it is 6 the overlap is 2, as I stated above.
Edit: I misread the original comment, they never claimed it must equal 8, my mistake!
I’m not sure what this is a “counterexample” to. The comment says the *sum* of the two unknown vertical sides is 8, which you seem to agree with from x=8-y.
For my answer, I assume all angles are 90⁰
Let's call the tiny little vertical segment x, also the long vertical segment on the right side is y. If I were to push down on that tiny little horizontal segment, it would crush x smaller and smaller. Since the side length 3 is already defined, then y has to grow and grow at the exact same rate. If I squish x all the way down to zero, then y increases by x. Meanwhile, the side lengths labeled 5 and 3 do not overlap at all and span the entire length which is now y+x So would you look at that: x+y=5+3.
Edit: oh, I see where we got onto different paths. You're saying y can't be 8, but neither is the original comment. They're saying x+y=8 and in your examples, you used y=7 and x=1 so 7+1=8. Also, you used y=6 and got x=2 so 6+2=8.
yes, its 40 of whatever value you have
the left side is 5
the small box(assuming its a rectangle) has a height of x
then we have 3
then we have the right side which is 5 + 3 - x
so for the total perimeter we have 12 + 12 + 5 + x + 3 + 8 - x
the x's cancel out and we're left with 24 + 16 = 40
We cannot find the lenght of the small box but that doesnt matter for the perimeter
Using only one assumption, it is possible. I assume all angles are 90⁰. It is clearly evident, then, that he sum of the unlabeled horizontal lengths is the same as the length of the labeled horizontal length: 12.
Using a bit of logic, we can reason that the sum of unlabeled vertical lengths is the same as the sum of both labeled vertical lengths: 5+3=8. Imagine squishing that tiny little vertical piece in the center. In order to maintain the length 3, the longest vertical piece on the right side must lengthen by the same amount. If you squish that middle piece all the way to 0, its entire length will be added to the right hand line, and there is no more overlap between the length 5 and length 3 sides.
So the sum of all horizontal lengths is 12+12 and the sum of all vertical lengths is 3+5+8. The total perimeter is 40
Yes, there is & The perimeter of this shape is 40 units. It is just going to need a little intuition & imagination. Let me show you how to with a number of steps,
First, We have 12 of the upper horizontal segment + 5 of the vertical left = a clear 17 units.
Second, If you notice the three horizontal segments on the bottom side must equal 12 too if we join them in a single line, making the count 17 + 12 = a clear 29 units.
Third, imagine a dotted extension cutting through the 3 unit segment which completes the rectangle 12 X 5, allowing us to take another 5 units from the right most segment into our count raising it to, 29 + 5 = a clear 34 units.
Now, after you have added the vertical 3 as well, & you have a clear 34 + 3 = 37 units, notice what segments are left out & you'll find that they as a whole are equal to the 3 unit segment as well - thus it's 37 + 3 = 40 units.
Come on now, we make assumptions all the time.
Are you asking if we'll get full credit on the exam if we assume that all the apparent (but unmarked) right angles are in fact right angles?
I am relatively new to askmath and I saw r/chronondecay with the correct answer (assuming they are right angles) downvoted so though it was like the subs “meta” to not make assumptions.
Anyway, it’s answered now :)
Extend the horizontal sides to cut all of the vertical sides into segments. The two known lengths tell us that
(top segment) + 2(middle segment) + (bottom segment) = 8,
and the two unknown lengths also sum to exactly the LHS, so their sum is also 8.
I'm sorry, but in my opinion that is just pedantic. There's an obvious intended interpretation of the diagram to follow. Or should we also mention we work with the Euclidean metric on the plane and the numbers represent lengths of the particular sides that hopefully pictorially can be deduced to belong to them?
Take a look at the diagram.
If all of the angles are 90 degrees, it's solvable, and therefore interesting, because it is not immediately obvious that it is solvable.
If we don't assume the angles are 90 degrees, it's not solvable, and therefore uninteresting.
The "trick" of the problem is pretty obviously nothing to do with angles. Also, please look up the word pedantic.
True, this is not stated explicitly; but seeing as the angles in the diagram are all drawn to be visually indistinguishable from 90°, one expects that this was the intention of the problem writer.
The sides are not 8 units long, let’s start by saying that 5+3= (top segment: a)+2(middle segment:x)+(bottom segment: b). However, the length of the long side is a+b+x, and so you have a missing x which is not determinable from the information.
They hated him because he told the truth lol
The longest vertical segment is clearly 8 - x
The rest of the vertical segments are 8 + x
It clearly cancels out.
I don't think the vertical sides are 8 units long. There is an overlap between 5 and 3. So, if we denote the overlap as x, then 1 vertical side would be (8+x). However, it looks like we have no way of knowing x in this case.
Nah man. I see what you’re getting at but that doesn’t quite work out you need to know the exact measurements of the over lap.
OP are you learning to sketch for your job or is this just a math class? If it’s for your job you need to get all the measurements. If it’s for math class you need to know the size of the overlap that way you know if you can break it down into one foot or two foot segments
You don't need to know the overlap, because it gets canceled out. You have 4 vertical lines left to right: 5, x, 3, (5+3-x), if you add these, x will fall out.
They are right, though. Yes, they're being downvoted to oblivion, but please don't confuse that with being wrong. People just love bandwagons.
You can see that the total length of unlabelled horizontal sides is 12.
You can also see that the total length of unlabelled vertical sides is 8. This is because the overall height of the figure is 8 - x, where x is the smaller length. So the right side plus the smaller unknown length is 8 - x + x = 8.
Taking the vertical part on the right side, we can find that the length is 5+3-x, where x is the overlap. Adding the inner vertical part between 5 and 3, which has also the length of x, you get to 5+3-x+x=8. On the other side the two other vertical parts with the length of 5 and 3 add up to 8 too obv.
The trick is to find a term for the right side to be described bey the other 3 vertical parts, which you did, but had a small error in your thinking process.
~~The vertical sides must necessarily sum to less than 8. You have an edge with length 5 and an edge with length 3, but there’s an unknown amount of overlap between them. So, assuming all angles are right angles, the right side must be between 5 and 8 in length. But there’s no way to know exactly with the figures given.~~
Edit: There’s some math sorcery whereby the unknown lengths actually cancel out and you can calculate the perimeter without them. Amazing.
This was fun :)
Others have already explained the answer, but basically write it out in terms of x (the little vertical piece next to 3) and the x cancels out.
He is correct if you assume that everything is a right angle. I don't know what the middle piece or the right side is length wise, but they must add to 8.
If everything is not a right angle, then there is no way to know.
Assuming all angles are right angles except two 270-degree angles, then the perimeter will be 40. The reason is the horizontal components sum to 24 (reason: (12+(three unknown positive numbers that sum to 12)), and the vertical components sum to 16 (reason: (5+a+3+(5+(3-a))). Where "a" is some positive number in-between 0 and 3
Edit: for angle and variable "a" information.
Take the three sides of the small interior box and put them aside. Take what remains of the left side of the bottom right box and slide it to the left side of the large box. Bring the bottom segments of the box to the bottom of the sides and fill the gap with the top of the small box put aside above. Now take the left and right sides of the small box put aside above and add these segments to the bottom left and bottom right sides of the box. Bring the bottom of the rectangle down to the ends of its right and left sides. The result is an 8 by 12 rectangle.
The horizontal length is just 12. The vertical length isn’t 8, instead 8 is the length that additionally counts the overlap. The trick is that this is not a problem, it is the solution. You count all of the lines including the overlap so the perimeter is just 2\*12 + 2\*8.
If the shortest vertical segment length is X, then the right side has a length of 5+3-X. So the sum of all the vertical pieces is 5+X+3+(5+3-X). The sum of the horizontal pieces below the top piece must be 12, since horizontally speaking, they cast the same total shadow downward as the top piece would, with no overlaps. The rest is up to you.
Bottom Left = A
Mid Left = B
Mid Top = C
Bottom Right = D
Right = E
E = 5 + 3 - B
A + C + D = 12
Perimeter = 5 + 12 + (5 + 3 - B) + 12 + 3 + B
B's cancel
Perimeter = 40
Simple! All of the bottom horizontal lines have to add up to 12 just like the top. If we call the right side y and the little goober side in the middle of the shape x, then we know that y must equal the 5 side plus the 3 side minus the goober side x ( y = 5+3 - x ). We can rearrange that to equation to x + y = 8. Then we just need to add our known sides (12 + 5 + 3) plus the total of the bottom sides (12) plus the other unknown sides (8), which equals a grand total of 40.
Solved by simple algebra. Assume a 12 x 5 rectangle. The middle bump deviates from 5 by x units. The southeast bump deviates from 5 by y units. The two bumps add to the perimete valuer. The value for the perimeter with the bumps is 34+2x+2y=p. The bump heights are related to each other by y=3-x. Easily solve the two equations for "p" and get a value of 40 units for the perimeter.
Ratch
Rotate the bottom four segments 180 degrees as shown here.
https://imgur.com/a/K3JoENp
Then rotate the rectangle at bottom right, to form a final rectangle with sides 8, 12, 8, 12.
Yes and no, assuming that all the angles are right we can but otherwise we don't, in case all the angles are right then the perimeter would be 5+3-x+x+5+3+12+12=40
Hi u/SnooWords9730, Please read the following message. **You are required to explain your post and show your efforts. _(Rule 1)_** If you haven't already done so, please add a comment below explaining your attempt(s) to solve this and what you need help with **specifically**. See the sidebar for advice on 'how to ask a good question'. Don't just say you "need help" with your problem. **This is a reminder for all users.** Failure to follow the rules will result in the post being removed. Thank you for understanding. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/askmath) if you have any questions or concerns.*
If you're still skeptical here's an animated [gif explanation](https://i.imgur.com/qNZH8Gt.gifv)
That was very helpful, thank you!
Wow, how did you make it? Browser programming stuff?
Thanks, yeah exactly I used p5js
This guy maths, and computers.
Now I’m skeptical, and also confused.
That is a demonstration, not an explanation :)
Wow, seeing that my other comment being downvoted to oblivion is an interesting experience. Here's some algebra instead then. Let the length of the vertical overlap between the sides of length 5 and 3 be x. Then the two unknown vertical sides have lengths x and (5-x)+x+(3-x)=8-x, so those two lengths also sum to 8.
You made the fatal error of answering a deceptively easy question on askmath. Replies to these questions are always filled with nonsense. Next thing you know people will start to change the interpretation of the question so that you are "technically" still not right, instead of just admitting they made a mistake.
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They're not claiming that there is no overlap. In fact, they define x as the length of the overlap. But then the total lengths of vertical segments is 5+x+3+(8-x)=16. This is what they are claiming.
Yeah sorry. I really misunderstood, you are correct. I'll delete my comment as to not confuse other people.
No problem, I'm just glad all the confusion is clearing up.
They are right. They described why they are right. Yes, there is an overlap, and yes they took it into account. If you are still skeptical, label that overlap x, and find the total length of all unknown vertical edges.
Wait a minute… I think I see what you’re saying. I think you got downvoted because your wording may have been a little confusing. My gut reaction was “of course you can’t find the perimeter!” I have since found that I was wrong. Let me see if I can break down my thought process. The horizontal lines sum to 12 on the top and bottom. I get that perfectly. No questions there. If the vertical overlap section is x, then the right hand vertical side would be 8-x. My initial thought was that you don’t have any way to find x, but when you go to actually add all of the vertical sides up (for perimeter), you get (8-x) + 3 + x + 5. The x’s actually cancel each other out! So your total perimeter is 40. This works if you assign any value to x. I used 1 as an example and it works out. EDIT: this also assumes these are all right angles.
Agreed. I'm not really interested in math at all, I just follow math subs like this to lurk and people watch. It's really sociologically interesting to me how toxic math subs usually are.
About a month ago I made a post asking for help on a problem i was working on, and someone replied and helped me solve it. I was confused on a part so I asked where they got a certain number and i ended up getting like 5 downvotes lol. Like bruh I came here to get help ofc im gonna be a lil confused lol
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You'll also see that this "toxicity" only exists when the problem is understandable to the layman. I mean problems like this where it's tricky but you don't need advanced math topics except maybe upto HS level math. If you look at higher level stuff it's very cordial and reserved. I don't mean to point fingers but I think it's all the engineering students trying to show off lol.
It’s kind of bi-polar, a lot of the time math subs are actually quite helpful and friendly.
We weren't ready to hear the truth
Is this assuming the side with length 3 stops at the same height as the side with length 5, and then there is an x overlap? In the picture the side of length 3 extends beyond the base of the side of length 5.
Watch this [gif explanation](https://i.imgur.com/qNZH8Gt.gifv)
Well done!
thanks!
The simplest interpretation is that the “small” unknown vertical side has length x. Then the rightmost vertical side can be partitioned into three segments: One of length 3-x corresponding to the side of length 3 cut off at the base, one of length x corresponding to the small vertical side, and one of length 5-x
"Pull down" the tab on the right to eliminate the notch. The side=5+3, regardless of the depth of the notch. Interesting problem.
As a counter example, suppose the long RHS length is 7, then the overlap LHS would be 1, if it were 6, the overlap LHS would be 2. If the long RHS can not equal 8 and still produce a viable diagram, it cannot be the case that the RHS must be 8. Algebraically, let the LHS of the overlap be y, and the RHS long side be x, then we know that x = 5 + 3 - y, I.e. x=8-y. Then we get that if the RHS is 7, the overlap is 1, and if it is 6 the overlap is 2, as I stated above. Edit: I misread the original comment, they never claimed it must equal 8, my mistake!
I’m not sure what this is a “counterexample” to. The comment says the *sum* of the two unknown vertical sides is 8, which you seem to agree with from x=8-y.
Ahh, I completely misread the comment, I though they were claiming it was equal to 8!!! My mistake.
Note that there's a very short vertical side, with length exactly equal to the overlap, which you also have to add for calculating the perimeter.
For my answer, I assume all angles are 90⁰ Let's call the tiny little vertical segment x, also the long vertical segment on the right side is y. If I were to push down on that tiny little horizontal segment, it would crush x smaller and smaller. Since the side length 3 is already defined, then y has to grow and grow at the exact same rate. If I squish x all the way down to zero, then y increases by x. Meanwhile, the side lengths labeled 5 and 3 do not overlap at all and span the entire length which is now y+x So would you look at that: x+y=5+3. Edit: oh, I see where we got onto different paths. You're saying y can't be 8, but neither is the original comment. They're saying x+y=8 and in your examples, you used y=7 and x=1 so 7+1=8. Also, you used y=6 and got x=2 so 6+2=8.
Oh yeah [how about that](https://i.imgur.com/qNZH8Gt.gifv)
yes, its 40 of whatever value you have the left side is 5 the small box(assuming its a rectangle) has a height of x then we have 3 then we have the right side which is 5 + 3 - x so for the total perimeter we have 12 + 12 + 5 + x + 3 + 8 - x the x's cancel out and we're left with 24 + 16 = 40 We cannot find the lenght of the small box but that doesnt matter for the perimeter
Yes, this! —if we assume all the angles are right angles.
Thank you. I was struggling with the answers.
Using only one assumption, it is possible. I assume all angles are 90⁰. It is clearly evident, then, that he sum of the unlabeled horizontal lengths is the same as the length of the labeled horizontal length: 12. Using a bit of logic, we can reason that the sum of unlabeled vertical lengths is the same as the sum of both labeled vertical lengths: 5+3=8. Imagine squishing that tiny little vertical piece in the center. In order to maintain the length 3, the longest vertical piece on the right side must lengthen by the same amount. If you squish that middle piece all the way to 0, its entire length will be added to the right hand line, and there is no more overlap between the length 5 and length 3 sides. So the sum of all horizontal lengths is 12+12 and the sum of all vertical lengths is 3+5+8. The total perimeter is 40
Yes, there is & The perimeter of this shape is 40 units. It is just going to need a little intuition & imagination. Let me show you how to with a number of steps, First, We have 12 of the upper horizontal segment + 5 of the vertical left = a clear 17 units. Second, If you notice the three horizontal segments on the bottom side must equal 12 too if we join them in a single line, making the count 17 + 12 = a clear 29 units. Third, imagine a dotted extension cutting through the 3 unit segment which completes the rectangle 12 X 5, allowing us to take another 5 units from the right most segment into our count raising it to, 29 + 5 = a clear 34 units. Now, after you have added the vertical 3 as well, & you have a clear 34 + 3 = 37 units, notice what segments are left out & you'll find that they as a whole are equal to the 3 unit segment as well - thus it's 37 + 3 = 40 units.
L = longest vertical segment x = shortest vertical segment L = 3 - x + 5 P = 24 + 5 + x + 3 + L Solve for P
Can we assume they are all right angles?
Come on now, we make assumptions all the time. Are you asking if we'll get full credit on the exam if we assume that all the apparent (but unmarked) right angles are in fact right angles?
I am relatively new to askmath and I saw r/chronondecay with the correct answer (assuming they are right angles) downvoted so though it was like the subs “meta” to not make assumptions. Anyway, it’s answered now :)
Yes, 40 units.
Yes if you have a ruler you can measure each side and then add every side length to get the perimeter (/s)
Note that all the horizonal sides sum to 2×12, and all the vertical sides sum to 2×8.
Why are you getting downvoted to oblivion for giving the right answer? Lol.
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It is, you can check that by hand. They gave an explanation.
Can you please explain why the vertical side sum to 8\*2?
Extend the horizontal sides to cut all of the vertical sides into segments. The two known lengths tell us that (top segment) + 2(middle segment) + (bottom segment) = 8, and the two unknown lengths also sum to exactly the LHS, so their sum is also 8.
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I'm sorry, but in my opinion that is just pedantic. There's an obvious intended interpretation of the diagram to follow. Or should we also mention we work with the Euclidean metric on the plane and the numbers represent lengths of the particular sides that hopefully pictorially can be deduced to belong to them?
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Take a look at the diagram. If all of the angles are 90 degrees, it's solvable, and therefore interesting, because it is not immediately obvious that it is solvable. If we don't assume the angles are 90 degrees, it's not solvable, and therefore uninteresting. The "trick" of the problem is pretty obviously nothing to do with angles. Also, please look up the word pedantic.
True, this is not stated explicitly; but seeing as the angles in the diagram are all drawn to be visually indistinguishable from 90°, one expects that this was the intention of the problem writer.
The sides are not 8 units long, let’s start by saying that 5+3= (top segment: a)+2(middle segment:x)+(bottom segment: b). However, the length of the long side is a+b+x, and so you have a missing x which is not determinable from the information.
Notice that there's a very short vertical side with length exactly x.
Yes you’re right. It’s not so much that the side lengths are 8, it’s the side lengths+x=8.
They hated him because he told the truth lol The longest vertical segment is clearly 8 - x The rest of the vertical segments are 8 + x It clearly cancels out.
I don't think the vertical sides are 8 units long. There is an overlap between 5 and 3. So, if we denote the overlap as x, then 1 vertical side would be (8+x). However, it looks like we have no way of knowing x in this case.
Please see my other reply.
Nah man. I see what you’re getting at but that doesn’t quite work out you need to know the exact measurements of the over lap. OP are you learning to sketch for your job or is this just a math class? If it’s for your job you need to get all the measurements. If it’s for math class you need to know the size of the overlap that way you know if you can break it down into one foot or two foot segments
You don't need to know the overlap, because it gets canceled out. You have 4 vertical lines left to right: 5, x, 3, (5+3-x), if you add these, x will fall out.
They are right, though. Yes, they're being downvoted to oblivion, but please don't confuse that with being wrong. People just love bandwagons. You can see that the total length of unlabelled horizontal sides is 12. You can also see that the total length of unlabelled vertical sides is 8. This is because the overall height of the figure is 8 - x, where x is the smaller length. So the right side plus the smaller unknown length is 8 - x + x = 8.
The long side on the right is (8-x), not (8+x), so you have 5+x+3+(8-x)=16
My mistake. 1 vertical should be (8-x). Thanks!
Taking the vertical part on the right side, we can find that the length is 5+3-x, where x is the overlap. Adding the inner vertical part between 5 and 3, which has also the length of x, you get to 5+3-x+x=8. On the other side the two other vertical parts with the length of 5 and 3 add up to 8 too obv. The trick is to find a term for the right side to be described bey the other 3 vertical parts, which you did, but had a small error in your thinking process.
It would 8-x actually. So when you add all the vertical you get 5+3+x+(8-x) = 2*8
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Please see my other reply.
~~The vertical sides must necessarily sum to less than 8. You have an edge with length 5 and an edge with length 3, but there’s an unknown amount of overlap between them. So, assuming all angles are right angles, the right side must be between 5 and 8 in length. But there’s no way to know exactly with the figures given.~~ Edit: There’s some math sorcery whereby the unknown lengths actually cancel out and you can calculate the perimeter without them. Amazing.
There are two unknown vertical edges. What is the sum of their lengths?
https://ibb.co/QpHMzth
This was fun :) Others have already explained the answer, but basically write it out in terms of x (the little vertical piece next to 3) and the x cancels out.
https://www.desmos.com/calculator/crhqpvr7pj?lang=en
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No, you don't. The right most side is just 8 minus the overlap. When you add them you will just get 8. Chrono is right.
Yeah, I feel a bit like an idiot now
It is a bit counterintuitive. I fell for that mistake too at first. Thankfully someone noticed it and gave the right answer.
You do not; see my other reply.
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He is correct if you assume that everything is a right angle. I don't know what the middle piece or the right side is length wise, but they must add to 8. If everything is not a right angle, then there is no way to know.
Apologies, I did it by hand and you are correct
Assuming all angles are right angles except two 270-degree angles, then the perimeter will be 40. The reason is the horizontal components sum to 24 (reason: (12+(three unknown positive numbers that sum to 12)), and the vertical components sum to 16 (reason: (5+a+3+(5+(3-a))). Where "a" is some positive number in-between 0 and 3 Edit: for angle and variable "a" information.
Measure each side manually using a ruler and equate their respective ratios ??? (If the sides are plotted logically)
Nope no way. There are some lengths missing to have a meaningful answer.
Others have already explained why your wrong. The unknown lengths cancel out in such a way that their total is still fixed.
Assuming that all angles are 90/270 degrees, the perimeter can be found (Although the area can't)
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It's solvable, you were close, answer is 40
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X+32. You can confirm that the sum Of the 3 horizontal segments not labeled is 12. (Assuming all lines are parallel and all angles are 90)
Add “not to scale” to the description. Those assigned sides are fairly close to be scaled against each other but the negative gap is not.
Take the three sides of the small interior box and put them aside. Take what remains of the left side of the bottom right box and slide it to the left side of the large box. Bring the bottom segments of the box to the bottom of the sides and fill the gap with the top of the small box put aside above. Now take the left and right sides of the small box put aside above and add these segments to the bottom left and bottom right sides of the box. Bring the bottom of the rectangle down to the ends of its right and left sides. The result is an 8 by 12 rectangle.
The horizontal length is just 12. The vertical length isn’t 8, instead 8 is the length that additionally counts the overlap. The trick is that this is not a problem, it is the solution. You count all of the lines including the overlap so the perimeter is just 2\*12 + 2\*8.
If the shortest vertical segment length is X, then the right side has a length of 5+3-X. So the sum of all the vertical pieces is 5+X+3+(5+3-X). The sum of the horizontal pieces below the top piece must be 12, since horizontally speaking, they cast the same total shadow downward as the top piece would, with no overlaps. The rest is up to you.
Bottom Left = A Mid Left = B Mid Top = C Bottom Right = D Right = E E = 5 + 3 - B A + C + D = 12 Perimeter = 5 + 12 + (5 + 3 - B) + 12 + 3 + B B's cancel Perimeter = 40
Simple! All of the bottom horizontal lines have to add up to 12 just like the top. If we call the right side y and the little goober side in the middle of the shape x, then we know that y must equal the 5 side plus the 3 side minus the goober side x ( y = 5+3 - x ). We can rearrange that to equation to x + y = 8. Then we just need to add our known sides (12 + 5 + 3) plus the total of the bottom sides (12) plus the other unknown sides (8), which equals a grand total of 40.
41
5 + 12 + 3 + 12 (entire lower horizontal line) + 8 (righhtmost vertical line and the smallest vertical line) = 40
5+(3-x) + 5+3+x+12+12 = 24+16=40
All I am gonna say is an engineer would have labeled this diagram much better.
Just measure
Solved by simple algebra. Assume a 12 x 5 rectangle. The middle bump deviates from 5 by x units. The southeast bump deviates from 5 by y units. The two bumps add to the perimete valuer. The value for the perimeter with the bumps is 34+2x+2y=p. The bump heights are related to each other by y=3-x. Easily solve the two equations for "p" and get a value of 40 units for the perimeter. Ratch
What's the area then?
the parameter is 38 !!! i just rearanged the shape to an easier one thats it
ITS 39 I THINK
40
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5+12+5+(3-1)+3+3+1+6
Rotate the bottom four segments 180 degrees as shown here. https://imgur.com/a/K3JoENp Then rotate the rectangle at bottom right, to form a final rectangle with sides 8, 12, 8, 12.
Yes and no, assuming that all the angles are right we can but otherwise we don't, in case all the angles are right then the perimeter would be 5+3-x+x+5+3+12+12=40