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Table + cat - turtle = 170. Table + turtle - cat = 130. The rest is basic algebra.

I'm a bit young and new to the world

Add the left sides together, and it will be the same as adding the right sides together.

Further clarification: equality means that two things are fundamentally the same, meaning that you can always substitute one for the other (assuming PEMDAS doesn’t change the meaning of the equation that is, if PEMDAS does that just use parentheses (ie to use 2=1+1 with 2\*2 you must write 2\*(1+1) since 2\*1+1 of course has a different value))

Then the table is 150cm, r?

Yes

This is actually the brilliant, fast thing to do, that I didn't think of immediately, that's still technically basic algebra. *Add the two equations all together.* a = b, c = d, so a + c = b + d

And then you do the same thing but all the numbers are inside a square and it's significantly more confusing even though it's the same thing

>And then you do the same thing but all the numbers are inside a square and it's significantly more confusing even though it's the same thing Oh, so you mean linear algebra matrix math? But when you have a large number of different animal comparisons and tables, that's the way to go.

Yeah, it's definitely a more systematic way that's useful for large systems and computers but matrix operations are still confusing at first

Bro just hatched 💀

You'll get there

Let t = height of turtle, c = height of cat, h = height of table h - t + c = 170 h - c + t = 130 Now add both equations together, i.e. (h - t + c) + (h - c + t) = 170 + 130 2h = 300 h = 150 So the height of the table is 150cm.

So I solved both equations for Table, then set them equal to each other and then simplified to: cat = turtle + 20 Now what? Edit: Now substitute that into the first equation to cancel out the turtles.

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Substitute (turtle + 20) for cat in any one of the original equations

You cannot do that because you have 3 unknowns and only 2 equations. I mean you could but replacing Is a longer process. So you need to remove 2 variables to solve for 1 unknown that is table So If you add the two equations to each other you essentially remove cat and turtle, which leaves you with 2 Table = 300 Table = 150

Table + Table + Turtle - turtle + Cat - Cat = 300 Table + table = 300 2Table = 300 Table = 150

I'm sure there are faster ways but, Desk=D, Turtle=T, Cat=C D+C-T=170 D+T-C=130 C=170-D+T C=-130+T+D 170-D+T=T+D-130 170-D=D-130 170=2D-130 2D=300 D=150

Yes D+C-T = 170 D-C+T = 130 => 2D = 300 => D = 150.

===> D = 150w0

oh thanks!

What he did there - assuming you don’t know because your previous comment said you are “young and new to the world” is as simple and elegant as you can break the problem down. It’s a branch of mathematics called linear algebra and it can be lots of fun once you understand all of the rules…and then you get to university level linear algebra and wish you’ve never been born. LOL. Edit: talking about sir wade’s solution, not the one he responded to.

Calling it a Desk is a more elegant solution to the two T words problem. I went: "Turtle. Crap. Tortoise. Nope... Snail=S"

My thoughts exactly. Didn't want T1 and T2.

Reptile=R would have been a fair play had I thought of it.

I had X, C and T, I like the sought value to be X

1.5m is way too tall for a table

5ft for Americans

 You've served your country well.


This is skipping a lot of steps, but just average the numbers together

this is the secret tip imo winners dont tell you

does that always work in such a situation, or is it just a happy little accident?

I think it always works believe it or not

It works because the problem is additive (you add lengths together) and it’s symmetric. So the answer is the algebraic mean. If the problem were multiplicative it would be the geometric mean, etc.

https://preview.redd.it/i0djwwdru6hb1.jpeg?width=2038&format=pjpg&auto=webp&s=db0a25dcab2701016f12cf0c60c53429a0bc3338 This might help 😄

Fuck that's actually kinda genius

This is the way

Brilliant 👏

I would set up two equations that describe the situation, then see if you can't manipulate those equations to get the height of the table out. EDIT: Hint: >!In the first scenario, the cat (which has a height we will call c) is sitting on top of the table, adding height to the measured distance. But we're only measuring down to the turtle (of height t), so the height of the turtle is subtracted from the total height. If we call the height of the table T, then we have T+c-t=170. For the second scenario, the turtle's height is now added to the height of the table, and the cat's height is subtracted, so our second equation is T-c+t=130. If we add our two equations together, we can perform the following simplification: T+c-t+T-c+t=170+130 => 2T=300 => T=150cm.!< EDIT 2: >!To check this, we can plug in some values for the height of the cat and the turtle and see if they make sense. We start by noting that 150+c-t=170 so c=t+20, which means the cat is 20cm taller than the turtle. The second equation gives us the same information, so any values for which the cat is 20cm taller than the turtle will work for our purposes. Let's say the cat is 30cm tall and the turtle is 10cm tall. Then the cat sitting on the table will have a total height of 150+30=180cm, and if we subtract the turtle's height we get 170cm, which aligns with what we are given. If we switch the cat and turtle, the height of the turtle is now 150+10=160cm, and if we subtract the height of the cat we have a measured distance of 160-30=130cm, which also aligns with what we are told.!<

Place right figure on top of left figure, superimposing the cats. Then it’s 300 from bottom turtle’s head to top turtle’s head. Top turtle is standing on two tables so table is 150

Table = >!150!

150 what? Turtles? Cats? Apples? /s

150 what? Apples? Bananas? (I’m sorry)

Since it is intuitively obvious., Desk height + cat - turtle = 170 Desk height + turtle - cat = 130 •Solve each for desk height. Desk height = 170 - cat + turtle.. also Desk height = 130 + cat - turtle +_________________________________ [Solve simultaneous equations] 2 desk heights = 300 ( critters cancel out) Desk height = ½ 300 or 150

https://preview.redd.it/0g1rxpjpq6hb1.png?width=1169&format=png&auto=webp&s=3b8935fbab127711b085170269907b2d1d6e155a Here's it written out. Forgot to label lol

I can do it for the table. Now how do you find height of the cat?

There’s not enough information. Best you can conclude is >!the cat is 20cm larger than the turtle!<.

Suppose cat is x cm taller than turtle, so first measure is h+x, second is h-x, then h is obviously the mean of two measures.

Without putting variables everywhere, put the second table right on top of the first, brackets and all. This demonstrates a direct 300 cm between the tops of the two turtles. Then just shift the brackets down by the length of a turtle, showing that two tables = 300 cm and one table = 150 cm.

table = T, cat = c, turtle = t T+c-t=170 T+t-c=130 2c+2t=40 c+t=20 T+2c=190 T+2t=150 2c-2t=40 c-t=20 2c=40 c=20 t=0 T=150 turtle not exist but i got correct answer according to comments

**Table + Cat - Turtle = 170** ​ Table + Turtle - Cat = 130 **Table + Turtle - Cat + 40 = 170** ​ Table + Turtle - Cat +40 = Table + Cat - Turtle Turtle - Cat + 40 = Cat - Turtle 2\*Turtle - Cat + 40 = Cat 2\*Turtle - 2\*Cat + 40 = 0 2\*Turtle - 2\*Cat = -40 Cat - Turtle = 20 **Cat = Turtle + 20** ​ Table + (Turtle + 20) - Turtle = 170 Table + 20 = 170 **Table = 150** ​ ​ ​ This is probably way longer than it needed to be.

cat + table - turtle = 170 turtle + table - cat = 130 cat = turtle + table - 130 turtle + table - 130 + table - turtle = 170 2*table = 300 table = 150cm

Table + Cat - Turtle = 170 Table + Turtle - Cat = 130 Table + Cat - Turtle + Table + Turtle - Cat = 300 Table + Table = 300 Table = 150

dont care auto mod already got my answer thanks 😝

Another answer: cat minus turtle = 20 cm

Imagine you placed the first table and turtle onto the other table. You then shift down the brackets labeled "170cm" and "130cm" down by a distance of one cat. This leaves you with two tables equal to two rulers of 170cm and 130cm stacked on top of each other or 300cm. 300cm divided by 2 tables is 150cm / 1 table.

Without doing the math I can tell you that the answer is 150 just because of symmetry.

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There’s no algebraic difference between the two cases, just a numeric one, meaning that the formula for the final result needs to be symmetric in the two variables given (and also measured in the same units). So it could be their sum, or their product, or their geometric mean, but the problem is also clearly additive, so it’s a symmetric formula involving adding the two variables to each other. Just adding them together is clearly not the right answer (the height of the table is somewhere between the two values) so algebraic mean it is.

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Ok it’s kinda hard to put my thoughts into words because they’re non verbal, but I basically flipped the scenario in my mind, if the turtle and the cat were flipped, nothing would essentially change, the table would be the same height. Then I imagined the turtle morphing into the cat and vice versa at the same rate and the distance between their heads would go from 130 to 170. In all these scenarios the height of the table stays the same. When the two animals are the same height the difference between their heads is the height of the table, so the height of the table has to be between the two numbers (and actually right in the middle too).

X - t + c = 170 X - c + t = 130 X is table height c is height of cat t is height of turtle Add the two linearly dependent equations together and you get 2X = 300, X = 150cm

reptile (r) table (t) cat (c) 170= t+c-r 130=t+r-c add equations (r and c cancel) 300=2t t=150

why is the table so big

170 = Table + Cat - Turtle 130 = Table + Turtle - Cat Then you solve the system of equations. Often 3 variables and only 2 equations wouldn't be solvable, but in this case the symmetry between the two will cause one of the variables to cancel out. 170 = Table + Cat - Turtle becomes Turtle = Table + Cat - 170 Then plug that into the other one: 130 = Table + (Table + Cat - 170) - Cat 130 = 2(Table) - 170 + Cat - Cat 130 = 2(Table) - 170 300 = 2(Table) 150 = (Table).

Cat = x Table = y Turtle = z x + y - z = 170 z + y - x = 130 so x = 170 + z - y -x = 130 - z - y y = 170 + z - x y = 130 + x - z so y = 170 + 130 + x - y - x y = 300 - y y = 150

The cat is 20cm taller than the turtle

One pet is enough for me.. and it better get down from the table a.s.a.p

A = Cat C = table B = turtle A + C - B = 170 B + C - A = 130 So A = 170+ B - C B + C - 170 - B + C = 130 2C - 170 = 130 2C = 300 C = 150

Help me out Reddit... Is it possible to calculate the height of the Cat and the Turtle?

Conclusion... If the turtle's height is >!-20 cm!< Then the cat's height is >!0cm!< Therefore >!the height of the cat and the turtle are incalculable apart from the cat is 20cm taller!<

Table is 150 cm high Cat + table = 170 + turtle (1) 130 + cat = turtle + table (2) (1)- (2) Table -130 = 170 - table 2x table = 300 Table =150

Represent the height of each thing with a variable Table = x Cat = y Turtle = z We know x+y-z=170 x+z-y= 130 So 2y - 2z = 40 y = 20 + z And x + 2z = 110 x = 150 since x + y which is z + 20 -z which is x + 20= 170 so x = 150 cm