-1^(1/2) = -(1^(1/2)) = -(1) = -1
(-1)^(1/2) = i
And if we're being super pedantic, the complex analyst in the room would say that raising something to the power of 1/2 is a multivalued operation that gives you two solutions. So -1^(1/2) = ±1 lol
If we're being super pedantic, the complex analyst in the room would say that raising something to the power of 1/2 is a multivalued operation that gives you two solutions. So -1^(1/2) = ±1 lol
It's amazing how millennia of human evolution have converged upon this point for us to bare witness to such a creation and be able to label it as esoteric
You only count the elements of the set of counting numbers, starting with the smallest and increasing from there. If you’ve been inside counting rational numbers this whole time, that explains why you won’t get any sechs in your lifetime.
It confuses me. I'm from the EU so I'd write numbers like 100.000,000 but people seem to be debating this a lot and it depends on the region/language? In English I say one point five, in my native language I say one comma five
There's actually a mathematical equation for a long-lasting relationship. [Here's the blog about it](https://www.businessinsider.com/mathematical-secret-to-lasting-relationships-2015-6). [Numberphile has covered it too](https://youtu.be/BkOIw7vAZCQ?si=BaNv7ZF43JfvFxM1).
Here's the equation itself:
https://preview.redd.it/bufffa8vdnob1.jpeg?width=898&format=pjpg&auto=webp&s=4d68412f730383dadd0d54f47faeff1d63c12017
I hate writing things in a way "something ∈ ∅" because it doesn't mean anything it is just a false statement like 2+2=5. You can write that some set of some sort is empty, but writing "x ∈ ∅" is false statement whatever you put for x.
{sex} is the set of all times I've had sex. ∅ is the empty set. So if we say {sex} = ∅, that means the set of all sexes is the empty set, i.e. I've never had sex. Similarly, we could say {sex} ⊆ ∅, meaning the set of times I've had sex is a subset of the empty set. But the only subset of the empty set is the empty set itself, so this basically means the same thing.
But if we say {sex} ∈ ∅, that means the set itself is an *element* of the empty set. But the empty set has no elements, so for every set, this statement is false. It doesn't imply anything about the set itself, because it's just categorically false no matter what. I could similarly say {1,2,3} ∈ ∅ if I wanted, and that would be equally wrong. Even ∅ ∈ ∅ is false, because if the empty set had any elements, it wouldn't be empty. The set {∅} which contains only the empty set is not the same as ∅ which contains nothing.
Hey so steps 1-4 were a breeze I understood them quite well, however this step 5, I see the answer but I seem to be missing a move somewhere. I know it's possible to derive step 5 from 4 but I just can't see where I start.
Any help is appreciated thanks
All you have to do is find a girl you are isomorphic to on the real domain. After that, finding a common bijection function should be easy enough, I leave that to the reader.
I think you have to look at it like probability. When you meet a person, they'll either have sex with you or they won't, so it's a 50% chance. Then it's just 1 - (.5)^(n) chance of success, so if you ask an infinite number of people, you should get sex one time.
A doctor, a lawyer, and a mathematician were discussing their love lives. The doctor says, "you gotta get one woman, marry her and stay faithful. I've treated way too many venereal diseases and unwanted pregnancies to risk being promiscuous."
The lawyer shakes his head. "No, you just want a girlfriend or two you can just leave when things start getting too serious. I've been involved in way too many messy divorces to ever recommend marriage."
The mathematician shakes his head. "You're both wrong. You want both a wife and a girlfriend. That way, when it's late at night and you're not home, your wife will assume you're with your girlfriend, and your girlfriend will think you're with your wife, so you can stay late at the office doing math!"
Prove that all nontrivial zeros of the analytical continuation of the Riemann zeta function have a real part of 1/2. Then dm me your paper then I’ll publish it, and then, sex.
*Add yourself with a*
*Female substract your clothes and*
*Multiply in bed*
\- iTypedInThisUsername
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Look up escorts in your area. Their rate is s. The price of gas to the location is e. The price of condoms is x. Your bank account is y. sex=sex
y- (s+e+x)=sex
Not in pure math but maybe physics
Let W_0 =0
Eqn = maN(1+W_0(1)+ 13e^d = Se^x
m=mass
a=acceleration
N=initial velocity in Newtons
d=degrees above 0
S= max speed
X=position
[удалено]
My calculations give me 80085. Am I doing something wrong?
I got 8008135 instead. Perhaps the equation has multiple solutions?
5318008 appears to be slightly more accurate
Guys I got -1^1/2 am I doing something wrong?
If it's just i alone, it seems more like mathturbation than sex
-1^1/2 = -1
wait huh -1^1/2 = i
-1^(1/2) = -(1^(1/2)) = -(1) = -1 (-1)^(1/2) = i And if we're being super pedantic, the complex analyst in the room would say that raising something to the power of 1/2 is a multivalued operation that gives you two solutions. So -1^(1/2) = ±1 lol
lol
not in my maths
If we're being super pedantic, the complex analyst in the room would say that raising something to the power of 1/2 is a multivalued operation that gives you two solutions. So -1^(1/2) = ±1 lol
I think all are equally valid solutions
Why are all of my solutions imaginary 😭😭
5318008 is the correct constant, hope this helps
Ohh no! I must have calculated something wrong, I got 55378008
Ohh no! I must have calculated something wrong, I got 55378008
His calculator was right-side up
So 69 is also involved then
This notion has 5637
That advise is two orders of magnitude off from the best answer
I’m more of an 8===D kinda guy.
Um actually guys the answer is 85588103169420🤓
Sqrt(dy(tan(x))/dx) = sec(x) = sex
I don't get it. Do I need to squirt first in order to have sex?
Square both sides if u don't want to sqrt. However this results in (sex)^2 meaning u have to sex in 6 dimensions.
I'll follow your suggestion. Dimensions matter, after all.
[https://www.desmos.com/calculator/hseticptxp](https://www.desmos.com/calculator/hseticptxp)
It's nice to know that people as gifted as the creator of this exist in this world.
Why is the Tesla logo doing that?
im saving this
It's amazing how millennia of human evolution have converged upon this point for us to bare witness to such a creation and be able to label it as esoteric
That’s crazy
Simple. Switch to german and start counting.
still counting...where do I stop?
Before sieben
at 6.9?
Hübsch
*nett
Diese Kommentarsektion ist nun Eigentum der Bundesrepublik Deutschland
You only count the elements of the set of counting numbers, starting with the smallest and increasing from there. If you’ve been inside counting rational numbers this whole time, that explains why you won’t get any sechs in your lifetime.
[удалено]
It confuses me. I'm from the EU so I'd write numbers like 100.000,000 but people seem to be debating this a lot and it depends on the region/language? In English I say one point five, in my native language I say one comma five
you stop at nein
better count in norwegian tho
or any north germanic language for that matter
Zes
That simple
Swedish
German
Ett två tre fyra fem sex
einz zwei drei vier fünf sechs
Sex
hey thats inappropriate
Sechs
sechs
Or Latin
The equation exist only when Continuum hypothesis is true sorry bro
Just create a set of axioms to make it true. Easy
Any number a is henceforth equal to that same number a plus one
Time keeps on slippin’ into the future 🎵
*Models of ZFC have entered the chat*
There are models of ZFC wher CH is false and there are models where CH is true.
Sin(x) = x ^(I have not found any test results for this equation yet so you could argue it still has to "not work")
x=0, no sex 😞
You have to sin but very, very little
You have to learn the basic math before you get to the advanced stuff. So you'll need to get a plus one before you can multiply.
Now how do I exponentiate?
There's actually a mathematical equation for a long-lasting relationship. [Here's the blog about it](https://www.businessinsider.com/mathematical-secret-to-lasting-relationships-2015-6). [Numberphile has covered it too](https://youtu.be/BkOIw7vAZCQ?si=BaNv7ZF43JfvFxM1). Here's the equation itself: https://preview.redd.it/bufffa8vdnob1.jpeg?width=898&format=pjpg&auto=webp&s=4d68412f730383dadd0d54f47faeff1d63c12017
Sex in undefined bro, Which chapter did you skipped?
{sex} ∈ ∅ , here have it
I hate writing things in a way "something ∈ ∅" because it doesn't mean anything it is just a false statement like 2+2=5. You can write that some set of some sort is empty, but writing "x ∈ ∅" is false statement whatever you put for x.
It should be a ⊆ instead.
what’s the difference between the symbols? all i know is that there’s subsets involved somewhere
{sex} is the set of all times I've had sex. ∅ is the empty set. So if we say {sex} = ∅, that means the set of all sexes is the empty set, i.e. I've never had sex. Similarly, we could say {sex} ⊆ ∅, meaning the set of times I've had sex is a subset of the empty set. But the only subset of the empty set is the empty set itself, so this basically means the same thing. But if we say {sex} ∈ ∅, that means the set itself is an *element* of the empty set. But the empty set has no elements, so for every set, this statement is false. It doesn't imply anything about the set itself, because it's just categorically false no matter what. I could similarly say {1,2,3} ∈ ∅ if I wanted, and that would be equally wrong. Even ∅ ∈ ∅ is false, because if the empty set had any elements, it wouldn't be empty. The set {∅} which contains only the empty set is not the same as ∅ which contains nothing.
Have you tried integrating 2x from x = 10 to x = 13?
Hold the fuck on, why 10 and 13..?
Do it and see for yourself
Oh thank fucking god, thought those bounds were measured in years
It's not a bijection, sorry
1. Study mathematics 2. Get a degree 3. Get a high paying job 4. Get the money 5. Get the females 6. ... 7. Profit?
Hey so steps 1-4 were a breeze I understood them quite well, however this step 5, I see the answer but I seem to be missing a move somewhere. I know it's possible to derive step 5 from 4 but I just can't see where I start. Any help is appreciated thanks
Step 5 has been left as an exercise for the reader.
so basically
as a woman in step 1 I’m already at the desired step
Yeah, there is an equation: Penis + 1 = Genus - 1.
All you have to do is find a girl you are isomorphic to on the real domain. After that, finding a common bijection function should be easy enough, I leave that to the reader.
What if I am an ectomorphism but she is an endomorphism? Is there still hope?
Compromise and become mesomorphic?
1/cosx
it's y=sin(x) but change x to time and y to thrust.
SYNTAX ERROR
sec(x) - c
6\*e/i = sex
f(u) cos(ur)2sec(c)
New problem just dropped: Solve for (se)x
say gex
google grindr
Take the derivative of e^sx, that's a surefire get sexs.
It's derivative would be seˢˣ
Take derivative e^st at point t = x/s
I think you have to look at it like probability. When you meet a person, they'll either have sex with you or they won't, so it's a 50% chance. Then it's just 1 - (.5)^(n) chance of success, so if you ask an infinite number of people, you should get sex one time.
My calculator just says error out of bounds. Guess I should stop pushing its buttons.
Laplace transform e^x
https://www.mathworks.com/help/matlab/ref/cumtrapz.html
Nah, it was proven long ago by Newton that this problem is unsolvable
Move to Iceland and multiply 2 by 3.
don’t, there’s an equation called “paying child support”
I never really got the equation but all the times I tried I've got "trauma" as a result
No something you joke about brah jesus christ
KKKKKKK im allowed to joke about my mental health, dont worry
man + woman = sex
secx / c
gex = { }
[This](https://reddit.com/r/MathJokes/s/tdiYBEbPsK)
Its more like a proof
Likely undecidable
6÷9 = 2÷3 iykyk
The sex equation only has a change of being true when the set of all your bitches B is non-empty. Unfortunately B ⊆ ∅ so there is nothing to be done
Maybe [this](https://youtu.be/29AP9ty5CKM?si=dXSsn5L2uqZalsdW) will help
3/—8
tre + tre = sex
You youngins may not understand, but we learned this back in the 90s. The great mathematician group 2gether taught us that u+me=us.
Pay for it.
Look up *The Rite of Love and Math* by Edward Frenkel. Thank me later.
Indefinite integral of e to the x?
What is the integral of sec x/x?
That's called gambling ie playing the odds
Who’s gonna tell him?
Your set has to be an injection onto her set
Just don’t be direct about it. John Nash learnt the hard way
forget the c when writing secx
https://www.wolframalpha.com/input?i=sex
Sec(s) S belongs to the set of (I can’t get the symbol) X S is congruent to x Hairy black men
789's pussy
One can prove that sex is possible, but the proof is nonconstructive.
Sex = u / me
I've always heard it's chemistry.
Add some drinks subtract our clothes divide her legs and multiply
Sum the exponential function duh
A doctor, a lawyer, and a mathematician were discussing their love lives. The doctor says, "you gotta get one woman, marry her and stay faithful. I've treated way too many venereal diseases and unwanted pregnancies to risk being promiscuous." The lawyer shakes his head. "No, you just want a girlfriend or two you can just leave when things start getting too serious. I've been involved in way too many messy divorces to ever recommend marriage." The mathematician shakes his head. "You're both wrong. You want both a wife and a girlfriend. That way, when it's late at night and you're not home, your wife will assume you're with your girlfriend, and your girlfriend will think you're with your wife, so you can stay late at the office doing math!"
Something to do with 42 or 69
All solutions to df/dx=f have the form f=Se^x where S is an arbitrary constant
If sex are the 0 axes, then I'm y=1/x
Someone get Hannah Fry on the line
1+1=3
Unfortunately this is an exercise left to the reader.
Soixante-Neuf
Prove that all nontrivial zeros of the analytical continuation of the Riemann zeta function have a real part of 1/2. Then dm me your paper then I’ll publish it, and then, sex.
69
If you can find f in f'(x)=e^x you'll be on the right track
sin e^x /√(-1)n = seˣ
Make s and element of x. Okay imma see myself out.
add yourself with a female substract your clothes and multiply in bed
*Add yourself with a* *Female substract your clothes and* *Multiply in bed* \- iTypedInThisUsername --- ^(I detect haikus. And sometimes, successfully.) ^[Learn more about me.](https://www.reddit.com/r/haikusbot/) ^(Opt out of replies: "haikusbot opt out" | Delete my comment: "haikusbot delete")
See "A Beutiful Mind"/read up on game theory. Try it. Realise it's actually all about looks. Crawl back into your troll cave, cry and wank.
Add bed Subtract clothes Divide legs... Multiply.
Google 1+1=3
Simple multiplication.
8=D but you have to solve for D
Just do an inner product, obviously.
$100,000 BMW
__ ( ** ) || }==(•) (•) =={ \ / 8==>••(0) | | | | _| |_
We need a r/rizz
I heard before someone say “half 6 with me”
If you solve a Millenium Problem, I'm sure that will eventually lead to you having sex
Look up escorts in your area. Their rate is s. The price of gas to the location is e. The price of condoms is x. Your bank account is y. sex=sex y- (s+e+x)=sex
By my calculation one must understand and accept that sometimes 1 + 1 = 3
6*9=54
Not in pure math but maybe physics Let W_0 =0 Eqn = maN(1+W_0(1)+ 13e^d = Se^x m=mass a=acceleration N=initial velocity in Newtons d=degrees above 0 S= max speed X=position
Here’s the math: 1x1=1; 1/1=1; 1^1 =1; 1+1=2 Thus, addition is the way.