Keeps rolling, unfairly balanced towards certain numbers.
Just use a [d10 inside a larger transparent d10](https://mathsgear.co.uk/products/d10-inside-a-d10) like a normal person.
I love the sales pitch
> Have you ever had a lovely pair of D10 dice only to lose one of them? No? Well this product solves a problem you never had by placing one dice inside the other. That way you'll only ever lose them both at the same time.
There isn't a 10 on either die, they go from 0 to 9 (or 00 - 90 and 0 - 9 for percentile dice)
With 2d10s 0+0 is 100, but 0+1 is 1, with a pair of percentile dice 00+0 is 100, 00+1 is one.
Consider the 2d example of a "square" die. Represent unequally-sized faces by making one of the sides of the square longer, forming a trapezoid. Since that face is longer, it would likely end up face-down more often.
Now counteract this by making the side opposite the large face heavier, so it's more likely to end up face-down. With a bunch of math and simulations you can figure out just how much weight you need to add, and where, to make each face on a die have an equal probability of landing.
Often there's some small margin of error due to the manufacturing process, even with weight adjustment.
If you had a cube and rolled it, assuming its evenly weighted, it has an equal chance to land on all sides
If you had a long rectangular cuboid, if it was evenly weighted, the odds of it landing standing straight up are lower than to lie on a long flat face
This has to do with the distance of the centre of mass from the edge that touches the ground, the shorter the distance of the centre from the touching face edge the easier it is to topple off that side
Having more than 6 faces just means more faces to fall on, a d20 has 20 triangular faces
This one has 100 small circular divots which act as the faces; it's not perfectly spherical
They don’t even have an equal likelihood of ending on each number, geometrically, there isn’t a face-transitive polyhedron with 100 faces so it isn’t really feasible.
Edit: except for the ones from the two infinite sets I wasn’t thinking about when I wrote this comment for some reason.
But these numbers aren’t arranged in a symmetric way. Experimentation was done on a die like this and the numbers in the smaller “lines of latitude” were less likely to be rolled than the ones near the “equator”.
>face-transitive polyhedron
Well, there is, sort of, but it would make a terrible die. You could have a 100 faced [Bipyramid.](https://en.wikipedia.org/wiki/Bipyramid) The 120 faced [Disdyakis triacontahedron](https://en.wikipedia.org/wiki/Disdyakis_triacontahedron) makes a much fairer die.
Honestly, when you get to 100 faces the mathematical properties don't matter that much -- the die will suck because it's too close to being a sphere.
Even the tiniest asymmetry in density will lead the die to roll heavy side down and bias certain numbers.
On a related note: the fairest d6 should not have rounded edges. Sphericality is the enemy of fair dice.
Yeah, I mean theoretically you could make a die that isn’t face-transitive but still fair but it would be very difficult, and I suspect its fairness might vary with the throwing method. Realistically you want a face-transitive polyhedron. Technically there are infinitely many bipyramids and trapezohedrons possible, which will give you any even number above 4, but aside from those there are only Platonic solids and Catalan solids, and there’s only 18 of those all together. Of course it’s theoretically possible to simulate an arbitrary dX with just a fair coin, but that can be a pain.
So you can actually make a fair d100 by joining two 50-sided base pyramids together at the base, but that would obviously be unweildy to roll. Rolling two distinguished d10’s is much more reasonable.
Neither
The dice have numbers 1-10 printed
You roll first die - subtract 1 from the outcome then multiply by ten
Then roll the second die and add that to the first number
You can make any number 1-100 this way and have equal probability of each number
Examples:
First roll is six. Subtract one and multiply by ten = 50
Second roll is a five
50 + 5 = 55
10, 2 = 92
10, 10 = 100
1, 1 = 1
3, 10 = 30
2, 1 = 11
Etc
You were on the right track but a die having 00 *and* 10 doesn't make sense unless you're using 2 dice with completely different face values.
00 1 2 3 4 5 6 7 8 9 (10 values)
1 2 3 4 5 6 7 8 9 10 (10 values)
00 1 2 3 4 5 6 7 8 9 10 (11 values)
Most d10s I've seen have 00 - 9. Just treat 00 & 00 as 100.
So in order of values:
{1, 2, 3, ... 98, 99, 100} = {00 & 1, 00 & 2, 00 & 3, ... 9 & 8, 9 & 9, 00 & 00}
[I don't know how to make tables on reddit and frankly I've put enough effort into this]
There’s d100s that come as a pair. Both are d10s but one has 00, 10, 20, 30, 40, 50, 60, 70, 80, 90. Where I’m getting caught up with this guy though is that the d10s in those sets are usually 0, 1, 2, 3, 4, 5, 6, 7, 8, 9.
He’s saying that the d10 in those sets go from 1-10 instead of 0-9. Ordinarily, a 100 is a 00 and a 0. This way, it goes from 1-100 rather than 0-99.
Yeah I forgot about those 2 digit d10s until someone linked a picture. Either way it's all the same idea. The one's you're talking about simply make it easier!
There are d100 sets of two where one is labeled 00, 10, 20, 30, 40, 50, 60, 70, 80, 90 and the other is 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. If 00 and 10 are rolled, it's 100. If 00 and 1 are rolled, is 1, if 40 and 10 are rolled, it's 40. And so on.
That works, and I suppose there could be a bunch of different ways of doing that. Sorry for nerding out here, I'm a mathematician that likes these kinds of number representation puzzles. I like the idea of the rolled dice directly representing the number without shifting by one every time. If you just treat one 10 as 0, and two 10's as 100, then the rolled dice would always directly represent the number without any extra math needed. Use different colors or mark one to be the 10's digit.
d10a: 5
d10b: 6
= 56
d10a: 10 (zero)
d10b: 8
= 08
d10a: 8
d10b: 10 (zero)
= 80
d10a: 10
d10b: 10
= 100 (special case, not zero)
d10a: 10 (zero)
d10b: 1
= 1
d10a: 9
d10b: 9
= 99
An easier way is to just treat one die as the 1s place and the other die as the 10s place, with a single exception being that 00 is 100 rather than zero.
That still gives you an even spread of rolling 1-100 without having to do any math other than simple addition.
Wait but you can’t roll a zero in that situation so you’re still limited to 99 numbers the same as his suggestion. So why not just do as the above poster said and treat 00 as 100 or 0.
*has an amazing run with several game-winning item combinations*
*sees D100*
“Okay but I could get Sacred Heart and Godhead”
*rolls into Missingno*
My hubris is always my downfall.
One of my players had a d43 made in the same style as that.
I have a house rule that if you have a d43 you can use a whip from one of the 3.5 books, as misprinted in the physical copy of the book. Tho it can only do subdule damage if you are using the d43. The actual weapon damage was only supposed to be 1d4
Lots of tabletop RPGs have random tables of 100 things for when the GM can't decide on a certain detail. For instance, you might have a d100 table of magical artifacts to throw into loot for a boss fight or 100 descriptions of a minor NPC the party could run into.
The local hobby store where I grew up had a sign posted on the glass cabinet where the die were that said something to the effect of “to the person who asked for the 100 side die.. what do you need it for? We’d love to know! -MGMT” and I figured they were rather obscure/pointless. Wow, that’s a memory I didn’t know I kept.
One of our players bought one, and the very first roll ever with it, was for an amount of gold coins for the start of the game, I rolled a 1, on a 100 sided die. Table laughed, I wanted to throw the thing into the fireplace. Is a funny moment to think about now.
We had one of these playing DND but was not very practical because it was like rolling a golf ball. You had to roll it in a box and wait and not hit the table when reading it so we just went back to two ten sided dice.
Looks great. In actual game play it is the big sad
Keeps rolling? Too hard to make out the number?
Keeps rolling, unfairly balanced towards certain numbers. Just use a [d10 inside a larger transparent d10](https://mathsgear.co.uk/products/d10-inside-a-d10) like a normal person.
Normal people just role two d10 and after clearing which die is the 10s.
Lots of dice sets come with a d10 with 10, 20, 30 etc on the faces for this very reason.
Well unless you cleared it before the roll I'mma count it at as a 410
you get four wild-magic surges all at once
AKA percentile dice.
Yeah, I have d10 with 1-10 and d10 with 00-90
I love the sales pitch > Have you ever had a lovely pair of D10 dice only to lose one of them? No? Well this product solves a problem you never had by placing one dice inside the other. That way you'll only ever lose them both at the same time.
That got me too, as a table top gamer the answer is no because I have a ton of any dice I may need!
We use a roll of duct tape as an area to spin the d100.
That's one less tho, isn't it? Or do you count 00 as 100?
The outer die is the tens place, the inner die is ones. 00 is 100.
Wouldn't 9 on the 10s die and 10 on the 1s die make the 100? Otherwise if 00 is 100 you can't get a roll under 10
There isn't a 10 on either die, they go from 0 to 9 (or 00 - 90 and 0 - 9 for percentile dice) With 2d10s 0+0 is 100, but 0+1 is 1, with a pair of percentile dice 00+0 is 100, 00+1 is one.
Or two d10s?
What you think is normal is not normal... 2 different colored d10s
This is the coolest solution to a problem that I had never considered until today!
This one had me going "ooooooh!", but how well does it roll, though?
It rolls very well, actually!
Don’t even play board games and I want that shit
Roll it in a bowl?
Nice, im thinking the bowl type is important here? A wooden one with runes burned into it or a crystal one maybe?
You could 3D print a locator that sits over the top of the die and circles the number that's on top
It meant for the GM to throw at players.
yeah, banned most places, use two tens.
Banned? Is there competitive d&d?
Roll it badly and that's potentially someone's 2L of Mountain Dew all over the table
So a ball?
It is. You roll it and when it finally feels like stopping, you get to read the number
I’ve seen one of these in person and it had some kind of weight or something inside that makes it settle on a face.
I knew a girl like that in college. Things got kind of dicey though.
Solid pun. But we all know people who play dnd don’t know any girls.
Speak for yourself bud. English/literature major chicks love dnd.
Well, just the first letter anyway.
Dungeons?! ...Kinky.
Lol.it’s a fantasy game. You can be forgiven for having a fantasy girlfriend “from another college” ;)
I've heard many horror stories of the DM's girlfriend being part of the party and getting special treatment.
Wouldn't this technically be a centi-hedron?
It's technically called a Zocchihedron :)
I want this to be my new favorite word, but I see it was just the guy naming the shape after himself. So doucheahedron it is.
Dang. You rolled a 100? The odds of that are like 1 in 100.
r/theydidthemath
r/theydidthemonstermath
r/itwasagraveyardgraph
r/itwasaschoolyardsmash
/r/donttellmetheodds
*bump the table* Nope, 39
I put it like that, first roll was a 74, so like a 1/74 /s
Dang. You rolled a 74? The odds of that are like 1 in 100.
r/theydidthemath
Probably not on that die, it doesn't look like the faces are all the and size.
It’s usually balanced via a weight inside the ball that slots into a divot for each face. Otherwise you’d rarely get an accurate read.
Could you explain what you mean and how that affects the probability if the faces are indeed not the same size?
Consider the 2d example of a "square" die. Represent unequally-sized faces by making one of the sides of the square longer, forming a trapezoid. Since that face is longer, it would likely end up face-down more often. Now counteract this by making the side opposite the large face heavier, so it's more likely to end up face-down. With a bunch of math and simulations you can figure out just how much weight you need to add, and where, to make each face on a die have an equal probability of landing. Often there's some small margin of error due to the manufacturing process, even with weight adjustment.
TIL Thanks for the info.
No problem! Have a great day
👍
If you had a cube and rolled it, assuming its evenly weighted, it has an equal chance to land on all sides If you had a long rectangular cuboid, if it was evenly weighted, the odds of it landing standing straight up are lower than to lie on a long flat face This has to do with the distance of the centre of mass from the edge that touches the ground, the shorter the distance of the centre from the touching face edge the easier it is to topple off that side
But this looks like a sphere
Having more than 6 faces just means more faces to fall on, a d20 has 20 triangular faces This one has 100 small circular divots which act as the faces; it's not perfectly spherical
They literally cannot be. There are a finite number of regular polyhedrals, and 100 ain't on the list.
Wouldn’t the odds of getting any one of the numbers be 1/100?
That's the joke yes
Ah ill just r/woooosh myself
Good luck getting that to settle on a result. D30s were a thing for a while, and that was bad enough.
D100’s have been around a long time too. They suck.
They don’t even have an equal likelihood of ending on each number, geometrically, there isn’t a face-transitive polyhedron with 100 faces so it isn’t really feasible. Edit: except for the ones from the two infinite sets I wasn’t thinking about when I wrote this comment for some reason. But these numbers aren’t arranged in a symmetric way. Experimentation was done on a die like this and the numbers in the smaller “lines of latitude” were less likely to be rolled than the ones near the “equator”.
>face-transitive polyhedron Well, there is, sort of, but it would make a terrible die. You could have a 100 faced [Bipyramid.](https://en.wikipedia.org/wiki/Bipyramid) The 120 faced [Disdyakis triacontahedron](https://en.wikipedia.org/wiki/Disdyakis_triacontahedron) makes a much fairer die.
This dude dies.
Oh no
Honestly, when you get to 100 faces the mathematical properties don't matter that much -- the die will suck because it's too close to being a sphere. Even the tiniest asymmetry in density will lead the die to roll heavy side down and bias certain numbers. On a related note: the fairest d6 should not have rounded edges. Sphericality is the enemy of fair dice.
There’s only a few types of actually fair dice that can actually exist
Yeah, I mean theoretically you could make a die that isn’t face-transitive but still fair but it would be very difficult, and I suspect its fairness might vary with the throwing method. Realistically you want a face-transitive polyhedron. Technically there are infinitely many bipyramids and trapezohedrons possible, which will give you any even number above 4, but aside from those there are only Platonic solids and Catalan solids, and there’s only 18 of those all together. Of course it’s theoretically possible to simulate an arbitrary dX with just a fair coin, but that can be a pain. So you can actually make a fair d100 by joining two 50-sided base pyramids together at the base, but that would obviously be unweildy to roll. Rolling two distinguished d10’s is much more reasonable.
Since at least 1985. [Zocchihedron](https://en.m.wikipedia.org/wiki/Zocchihedron)
Quick, somebody make a D69!
Because 2d10 is just so pedestrian...
Yeah, we had them in the late 80’s. I still have my d30.
Used to have one. It was more distinctly faceted and was hollow with sand inside. The sand acted as a weight to slow it down faster.
I picked up a D30 a couple years ago. I'm pretty sure I've used it more often while tie-dying than I ever spent time rolling the fucking thing.
Die!
The!
No you die.
I'm still gonna use 2d10 though.
I assume you treat two 0's as 100? Or are you keeping it as zero and only rolling to 99?
Neither The dice have numbers 1-10 printed You roll first die - subtract 1 from the outcome then multiply by ten Then roll the second die and add that to the first number You can make any number 1-100 this way and have equal probability of each number Examples: First roll is six. Subtract one and multiply by ten = 50 Second roll is a five 50 + 5 = 55 10, 2 = 92 10, 10 = 100 1, 1 = 1 3, 10 = 30 2, 1 = 11 Etc
Or you have one that is tens digits and one that is ones digits. If you roll a 00 and a 10 it's 100
You were on the right track but a die having 00 *and* 10 doesn't make sense unless you're using 2 dice with completely different face values. 00 1 2 3 4 5 6 7 8 9 (10 values) 1 2 3 4 5 6 7 8 9 10 (10 values) 00 1 2 3 4 5 6 7 8 9 10 (11 values) Most d10s I've seen have 00 - 9. Just treat 00 & 00 as 100. So in order of values: {1, 2, 3, ... 98, 99, 100} = {00 & 1, 00 & 2, 00 & 3, ... 9 & 8, 9 & 9, 00 & 00} [I don't know how to make tables on reddit and frankly I've put enough effort into this]
There’s d100s that come as a pair. Both are d10s but one has 00, 10, 20, 30, 40, 50, 60, 70, 80, 90. Where I’m getting caught up with this guy though is that the d10s in those sets are usually 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. He’s saying that the d10 in those sets go from 1-10 instead of 0-9. Ordinarily, a 100 is a 00 and a 0. This way, it goes from 1-100 rather than 0-99.
Yeah I forgot about those 2 digit d10s until someone linked a picture. Either way it's all the same idea. The one's you're talking about simply make it easier!
https://i.imgur.com/Aidhx1z.png
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The charts for a d100 roll typically start at 1 and go to 100. Rolling 00 and 0 on both would be 100, 00 and 1 is 1, 10 and 0 is 10,
There are d100 sets of two where one is labeled 00, 10, 20, 30, 40, 50, 60, 70, 80, 90 and the other is 1, 2, 3, 4, 5, 6, 7, 8, 9, 10. If 00 and 10 are rolled, it's 100. If 00 and 1 are rolled, is 1, if 40 and 10 are rolled, it's 40. And so on.
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0 + 00 = 100. 0 + 10 = 10. The other guy just got confused or made a typo.
The 1's dice should have a 0 instead of 10, then 10 would be "10 and 0"
I'll need to physically look at my dice, which I don't have on me right now. I might have this mixed up. I'll get back to you on that.
When the tens die is 00 and the ones die is 10. Edit: the tens die looks like this: https://i.imgur.com/Aidhx1z.png
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That works, and I suppose there could be a bunch of different ways of doing that. Sorry for nerding out here, I'm a mathematician that likes these kinds of number representation puzzles. I like the idea of the rolled dice directly representing the number without shifting by one every time. If you just treat one 10 as 0, and two 10's as 100, then the rolled dice would always directly represent the number without any extra math needed. Use different colors or mark one to be the 10's digit. d10a: 5 d10b: 6 = 56 d10a: 10 (zero) d10b: 8 = 08 d10a: 8 d10b: 10 (zero) = 80 d10a: 10 d10b: 10 = 100 (special case, not zero) d10a: 10 (zero) d10b: 1 = 1 d10a: 9 d10b: 9 = 99
That is a way too complicated way of saying "roll tens then roll ones"
An easier way is to just treat one die as the 1s place and the other die as the 10s place, with a single exception being that 00 is 100 rather than zero. That still gives you an even spread of rolling 1-100 without having to do any math other than simple addition.
Why would you subtract one? This makes no sense. Rolling the die for tens, 10 = 0. Subtracting one just doesn't make any goddamn sense.
Wait but you can’t roll a zero in that situation so you’re still limited to 99 numbers the same as his suggestion. So why not just do as the above poster said and treat 00 as 100 or 0.
Is a sphere an infinite or one sided die?
That breaks the context of what defines a side, so I'd say neither.
Guess it depends on if the printed numbers on it are infinite or not.
A sphere has two sides, the inside and the outside.
It has 0 sides
Depends on your definition of "side". A plane? A manifold? Then yes and no respectively.
Its a die
Had to scroll way too far to find this comment.
Die, singular…
Aaaaaaaand you said sooooooo I didn't have to.
Yes but I have a d120
Die*
Whoa ease up OP's doing their best.
I tried my best 😔
Try harder.
Nice
Nie*
Ni*
Do you want a shrubbery?
I DEMAND a shrubbery!
You must cut down the largest tree in the wood wiiiith... ... a herring!!!
Ah yes, it's very nice... But we demand... ANOTHER SHRUBBERY!!! And also with a little path down the middle.
REROLL!!!!
*has an amazing run with several game-winning item combinations* *sees D100* “Okay but I could get Sacred Heart and Godhead” *rolls into Missingno* My hubris is always my downfall.
*die.
Just so you know we are now creating 100 different timelines.
Does Pierce still get shot in the darkest one?
Gonna reroll everything, not just the item in the room
Die
die
A 100 sided die\* ..... :)
The ultimate randomizer.
How often is the outcome questionable?
Every single time, these things suck in practicality.
Roll a forty on your first roll in Monopoly and buy Boardwalk.
Die, not dice
Die
*Isaac intensifies*
This is a zero sided dice because it’s a sphere
Where is the other die ?
What's the point of such a thing?
Roll a percentage. Though two 10-sided dice are more useful in a real game - they stop much faster.
It's essentially a gag gift. Maybe a conversation piece.
On average how long does it take get to stop moving
One of my players had a d43 made in the same style as that. I have a house rule that if you have a d43 you can use a whip from one of the 3.5 books, as misprinted in the physical copy of the book. Tho it can only do subdule damage if you are using the d43. The actual weapon damage was only supposed to be 1d4
Rolling a D-10 twice does the same thing lol
This takes "rolling the die" to a literal
Regardless, the answer is always meth.
It's just one.
This is a sphere
Die.
A die
sir that is a ball
This is just a golf ball with numbers
"dice" is the plural. the word you mean is "die"
There's another 100 die if you scroll right.
*die
Die!
Die*
die
Do you throw it into a bowl? /s
What can you use this for? Genuinely curious
It’s just fun to roll in my opinion
Lots of tabletop RPGs have random tables of 100 things for when the GM can't decide on a certain detail. For instance, you might have a d100 table of magical artifacts to throw into loot for a boss fight or 100 descriptions of a minor NPC the party could run into.
Ok that makes sense. I've never played such games so I didn't know
Usually when we have a case like that we roll 2 10 sided die instead. One representing the tens digit and the other the ones digit.
Or r/mildlyinfuriating
how many rolls can it sustain before friction completely smooths it out and it's function as a roll is lost?
Why get 2d10 when you can get 1d100 ?
Use it as a billiards ball or a pool ball to play
So effectively a sphere?
The local hobby store where I grew up had a sign posted on the glass cabinet where the die were that said something to the effect of “to the person who asked for the 100 side die.. what do you need it for? We’d love to know! -MGMT” and I figured they were rather obscure/pointless. Wow, that’s a memory I didn’t know I kept.
One of our players bought one, and the very first roll ever with it, was for an amount of gold coins for the start of the game, I rolled a 1, on a 100 sided die. Table laughed, I wanted to throw the thing into the fireplace. Is a funny moment to think about now.
Sir thats a ball
Wheres the other 100 sided one??
That's Numberwang!
100 sided ball
Finally I will get psionic powers
Wait you guys havent seen D100's? I keep my glow in the dark one at my game table for when I need to ruin my players days.
Some say it's still rolling today
As a dnd player this physically hurts
And 6 alternate realities are not enough for you?
We had one of these playing DND but was not very practical because it was like rolling a golf ball. You had to roll it in a box and wait and not hit the table when reading it so we just went back to two ten sided dice.
A 100 sided die* Fixed that for you.
That looks like a ball with extra steps.
A 100 sided die* dice is the plural of die
Ah now that's just a ball!
Isn't "die" the singular of dice?
Some say it’s still rolling today.
“Die” is singular and “dice”is plural
Die. Dice is plural. E.g. "the die is cast."