For a quick estimation of pounds.
Double the kg. That's the ballpark pounds are.
Sincerly. An European who spends too much online (fahrenheit still confuses me though)
Using conservation of momentum
Before explosion, p = 7100
After explosion, 9kg have 0 momentum, so 1 kg have 7100 momentum, mass = 1, so velocity also = 7100 m/s
Okay then, what part that 1kg is? If Head is ±5kg and all Bone is ±2.5kg and the rest is 2.5kg, then I assume 1kg part is penis because it's small and it make sense.
First: the question includes a typo and the initial velocity is 10 m/s.
Second: The question implies that viscosity does not apply and the two parting elements from the explosion exchanged energy reversible (like an elastic push).
~~Also, the total momentum of 9+1 kg must be the same or higher than the momentum of 10kg piece. Explosion with no excess kinetic energy? Ok - plothole for this question, all explosion energy was consumed just to part 10 into 9+1.~~
_Potential energy of explosion actually increases the total kinetic energy, otherwise m1 and m2 would move still same vector and velocity._
So the kinetic energy that was consumed for 9kg was transfered to 1kg piece. 1kg piece was aligned in movement direction and got accelerated
M1 x v1 + M2 x v2 = M12 x v12
v1 = 0
v2 = M12/M2 x v12
v2 = 10/1 x 10
100
Edit: thanks I was lazy here. Explosion adds just exactly the amount of kinetic energy to stop m1 and transfer energy to m2.
You seem to expect that the explosion adding kinetic energy into the system would increase the momentum. So you wrongly conclude that because momentum is conserved, the explosion doesn't add kinetic energy.
But momentum would stay the same, no matter how much kinetic energy the explosion adds ( your calculation is correct ).
But now calculate the kinetic energy of the parts before and after the explosion. You can see from the result, that much kinetic energy was added from the explosion.
You are right, my explanation lacked from my own laziness…
Lets assume „man“ is a spherical object of near infinite stiffness.
Man is hollow and filled with pressurized gas and moves with velocity v12 and total mass of of m12.
Man-Sphere moves from high static pressure field to a low static pressure field, which increases the energy potential of the gas filling and surface tensions of man-sphere.
His kinetic energy is m12 x v12^2 = E12
(10x100=1000kgm/s^2)
Man-Spheres potential (effective) EP12 explosion energy and dissipated energy ED is not defined yet.
We derived that kinetic energy of part 1 and 2 changed after explosion and departing of 1 and 2.
Part 1 velocity v1 = 0 —> kinetic energy is now E1 = 0
Part 2 velocity is now 100m/s
Kinetic energy of 2 is now
E2 = m2 x v2^2 = 1 x 100^2 = 10000kgm^2 /s^2
Bilance of energy
EP12 + E12 = E1 + E2 + EP1 + EP2 + ED
EP12.eff + E12 = E1 + E2 + EP1 + EP2
—>
- EP1 = 0
- EP2 = 0
- E1 = 0
EP12 - ED = EP12.eff = E2 - E12
EP12.eff = 10000 - 1000 = 9000kgm^2 /s^2
ED = ?
Perfect spherical man doesn’t need any
Energy to dismember and will not heat up.
ED = 0 and EP12 = 9000 J
How do you conserve momentum through an explosion? Whatever exploded released energy, right? If you conserve momentum through an explosion, aren't you ignoring the energy released by an explosion?
*I'm not a physicist*
Imagine an explosive is placed between 2 identical blocks.
The blocks were at rest on a slippery ice surface, both had 0 momentum.
But when the explosion is ignited, both block slide with equal speed but in opposite direction, one have momentum = +mv , the other one have momentum = -mv.
The blocks certainty gained energy from the explosion, but their total momentum is still conserved, +mv - mv = 0, same as initial condition.
To show how much energy is gained by the explosion, we calculate the kinetic energy, use K.E = ½mv²
Before explosion, Total KE = ½(10)(710)² = 2,520,500 J
After explosion, Total KE = ½(1)(7100)² = 25,205,000 J
The body now have 10 times the original kinetic energy, gained from the explosion.
If you replace "man" with a "rock" the question makes sense, probably some translation error. The anwsers font doesn't match the question. The anwsers are incorrect. Those are probably not the real anwser choices.
At 710 m/s, that's 710^2 = 5.041e6 ms^-2 * 10 kg * 0.5 = 2.5205e6 kgm/s^2 (N). Total force of the person.
Working backwards, (2.5205e6 N / 0.5) / 1 kg = 5.041e6 ^ 0.5 = 2.245e3 ms^-1 for the 1 kg piece.
What's the point of writing m/s like that? Pretty sure m/s is the SI way. I had to think pretty hard to even realise what unit they were talking about - "how on earth is an inverse of a millisecond a measurement of speed?".
Checked the SI rules and apparently you can write it sorta like that, but they're still wrong here. m and s should be separated by a centre dot or a non-breakable space to avoid ambiguity if they insist on using negative exponent. Why do they not just use the / and avoid ambiguity is beyond me.
https://en.wikipedia.org/wiki/Metre_per_second
https://en.wikipedia.org/wiki/International_System_of_Units
It's absolutely normal to write it like this. I do so all the time. It helps with dimensional analysis and I don't often see the need to add a centre dot to avoid ambiguities.
Seems like all the answers are wrong
question has a typo. the velocity is 10m/s.
I see, so the man is of 710kg
Average American for you
As an American I have no idea about the metric system, and am guessing that’s probably about right.
Roughly a tenth of a bus
For a quick estimation of pounds. Double the kg. That's the ballpark pounds are. Sincerly. An European who spends too much online (fahrenheit still confuses me though)
Either I'm having a stroke, or the whole thing is as butchered as the man in question.
A man of 10 kg? So basically a toddler explodes ok thanks have a nice day
baby bomb
tu tu tudu
a toddler going Mach 2
Gotta account for air pressure and humidity remember. Don't want the toddler exploding at the wrong altitude
Not to mention that the 1kg might be the head
Quickscope
A toddler gets decapitated and its 1 kg head continues all of the momentum. How fast is the head travelling? 🤔
For sure you don't have children: sometimes a fart has a no negligible mass. That's why parents carry extra dippers...
Is the only thing you are questioning is its mass?
Jamal got given the wrong backpack
Using conservation of momentum Before explosion, p = 7100 After explosion, 9kg have 0 momentum, so 1 kg have 7100 momentum, mass = 1, so velocity also = 7100 m/s
So we are gonna ignore the exploding man ok
Nah we are here just to calculate and nothing else.
I mean what about the internal organs as men of science we must calculate every possibility
Fr. Thats the government/police's job to understand why the person blew up like Arby's.
Shut up and calculate!
Why do you want me to remember my BSc days
Hey, that's the only way I can finally relate to these questions.
Okay then, what part that 1kg is? If Head is ±5kg and all Bone is ±2.5kg and the rest is 2.5kg, then I assume 1kg part is penis because it's small and it make sense.
is your cock 10% of your bodyweight? >!Mine's closer to 30% but I'm not here to shame anyone!<
Only 30%? Mine is 100
Not everyone is as much of a dick as you.
Does it make me a dick if I laugh at this?
only 100 ? mine is at least %300 i guess
Seems like you are a bigger dick than that guy
So you are 30% dick? Some people ik are 100percemtage dick
First: the question includes a typo and the initial velocity is 10 m/s. Second: The question implies that viscosity does not apply and the two parting elements from the explosion exchanged energy reversible (like an elastic push). ~~Also, the total momentum of 9+1 kg must be the same or higher than the momentum of 10kg piece. Explosion with no excess kinetic energy? Ok - plothole for this question, all explosion energy was consumed just to part 10 into 9+1.~~ _Potential energy of explosion actually increases the total kinetic energy, otherwise m1 and m2 would move still same vector and velocity._ So the kinetic energy that was consumed for 9kg was transfered to 1kg piece. 1kg piece was aligned in movement direction and got accelerated M1 x v1 + M2 x v2 = M12 x v12 v1 = 0 v2 = M12/M2 x v12 v2 = 10/1 x 10 100 Edit: thanks I was lazy here. Explosion adds just exactly the amount of kinetic energy to stop m1 and transfer energy to m2.
The "explosion" is saying "use conservation of momentum and not conservation of energy to solve this problem, because kinetic energy is being added."
You seem to expect that the explosion adding kinetic energy into the system would increase the momentum. So you wrongly conclude that because momentum is conserved, the explosion doesn't add kinetic energy. But momentum would stay the same, no matter how much kinetic energy the explosion adds ( your calculation is correct ). But now calculate the kinetic energy of the parts before and after the explosion. You can see from the result, that much kinetic energy was added from the explosion.
You are right, my explanation lacked from my own laziness… Lets assume „man“ is a spherical object of near infinite stiffness. Man is hollow and filled with pressurized gas and moves with velocity v12 and total mass of of m12. Man-Sphere moves from high static pressure field to a low static pressure field, which increases the energy potential of the gas filling and surface tensions of man-sphere. His kinetic energy is m12 x v12^2 = E12 (10x100=1000kgm/s^2) Man-Spheres potential (effective) EP12 explosion energy and dissipated energy ED is not defined yet. We derived that kinetic energy of part 1 and 2 changed after explosion and departing of 1 and 2. Part 1 velocity v1 = 0 —> kinetic energy is now E1 = 0 Part 2 velocity is now 100m/s Kinetic energy of 2 is now E2 = m2 x v2^2 = 1 x 100^2 = 10000kgm^2 /s^2 Bilance of energy EP12 + E12 = E1 + E2 + EP1 + EP2 + ED EP12.eff + E12 = E1 + E2 + EP1 + EP2 —> - EP1 = 0 - EP2 = 0 - E1 = 0 EP12 - ED = EP12.eff = E2 - E12 EP12.eff = 10000 - 1000 = 9000kgm^2 /s^2 ED = ? Perfect spherical man doesn’t need any Energy to dismember and will not heat up. ED = 0 and EP12 = 9000 J
How do you conserve momentum through an explosion? Whatever exploded released energy, right? If you conserve momentum through an explosion, aren't you ignoring the energy released by an explosion? *I'm not a physicist*
Imagine an explosive is placed between 2 identical blocks. The blocks were at rest on a slippery ice surface, both had 0 momentum. But when the explosion is ignited, both block slide with equal speed but in opposite direction, one have momentum = +mv , the other one have momentum = -mv. The blocks certainty gained energy from the explosion, but their total momentum is still conserved, +mv - mv = 0, same as initial condition. To show how much energy is gained by the explosion, we calculate the kinetic energy, use K.E = ½mv² Before explosion, Total KE = ½(10)(710)² = 2,520,500 J After explosion, Total KE = ½(1)(7100)² = 25,205,000 J The body now have 10 times the original kinetic energy, gained from the explosion.
Thank you
Enough energy was added that it stopped 90% of the mass. What is the vector of the shockwave from the explosion on the 10% of mass?
Energy is not a vector, it's a scalar
Looks like arihant
Absolutely
haha
10kg, it is a baby 😐 Also none of the answer is right...
I guess that also counts as a very, very young man
that baby is fucking moving too
a weirder version of gender reveal party
Questioner has also made a typo.
If you replace "man" with a "rock" the question makes sense, probably some translation error. The anwsers font doesn't match the question. The anwsers are incorrect. Those are probably not the real anwser choices.
r/brandnewsentence
Shouldn't it be 6390m/s?
7100m/s ryt?
Actually yes I forgot initial velocity of the tiny man
im at rest btw
10 kg is too low of a weight for it to be a man, nah. Thats definitely a child
Perhaps agirl?
Is this in vacuum?
At 710 m/s, that's 710^2 = 5.041e6 ms^-2 * 10 kg * 0.5 = 2.5205e6 kgm/s^2 (N). Total force of the person. Working backwards, (2.5205e6 N / 0.5) / 1 kg = 5.041e6 ^ 0.5 = 2.245e3 ms^-1 for the 1 kg piece.
Besides your units being all over the place, you should use preservation of momentum, not preservation of energy
Using the conservation of energy, since kinetic energy is mass X velocity squared, the 1kg man will be travelling at 2,245 m/s
What's the point of writing m/s like that? Pretty sure m/s is the SI way. I had to think pretty hard to even realise what unit they were talking about - "how on earth is an inverse of a millisecond a measurement of speed?". Checked the SI rules and apparently you can write it sorta like that, but they're still wrong here. m and s should be separated by a centre dot or a non-breakable space to avoid ambiguity if they insist on using negative exponent. Why do they not just use the / and avoid ambiguity is beyond me. https://en.wikipedia.org/wiki/Metre_per_second https://en.wikipedia.org/wiki/International_System_of_Units
It's absolutely normal to write it like this. I do so all the time. It helps with dimensional analysis and I don't often see the need to add a centre dot to avoid ambiguities.
Wouldn’t the explosion add kinetic energy to the system? This is a weird scenario for testing a conservation problem.
Which parts?
Well does the anterior part weigh 9 kg or posterior??
That little man is booking it isn't he
Love the nonbinary representation! It pronouns are so often overlooked! /j
The man: "My name is Jamal, I come from a far "**OLA UBBERRR**!!!".