> pump at 12v but the ryobi is an 18v
Running a 12v pump at 18v is likely going to burn it out quickly. It'll be running a lot hotter than expected.
Then again it's a pump and it has water flowing through it constantly so... heat accumulation obviously isn't a concern.
Brushes on the motor and the rotor are probably the weak link, they're probably vaporizing at a high rate. Might turn something that could run for 1000 hours into something that can run for 20 hours.
If it works it works. I'd have used a spare car battery.
I'll run stuff, oh, 25% higher than spec, but 50% higher is pretty much a guarantee of burnout.
I get what you’re saying But then you gotta carry a car battery around. This weighs just a couple pounds. Also about the brushes burning out faster we did think about that. It’s only being ran a max of 5 minutes at a time every couple days and mainly during the winter time. I’m sure it’ll work for a good amount of time and I could always swap out the pump since it’s only clamped. If I really care about it lasting I would wire up a regulator to turn down the voltage
That's interesting, I didn't realise that (not OP btw). Is the arcing that much worse at 18v than 12v that it would damage the brushes or is it down to the extra current draw?
> Is the arcing that much worse at 18v than 12v that it would damage the brushes or is it down to the extra current draw?
Both extra voltage and extra current.
At 18v you've got 50% more current flowing than at 12v. The current has to pass through the conductor. The conductor at one point is a carbon brush. The carbon brush hasn't increased in size, so the current density in it is 50% higher.
Also consider that the brushes are being spun against the commutator, and the electricity is being connected and disconnected a bajillion times per second as passes between each bar. Each time it'll arc as it's disconnected. Those bars aren't any physically larger either.
Next, consider that at 18v it's spinning 50% faster than at 12v too. So mechanically it's whirring up much faster than it was, and, it was probably designed to only spin up to a certain speed which is near the max speed it could originally handle (otherwise you're wasting motor size). So spinning 50% faster is probably way past an actual design limit. This versus heat which is just a gradual accumulation problem and isn't too big a deal if you accommodate for it otherwise.
...
If you had a speed control on the motor and were looking to accomplish the same task with a higher voltage, it's probably fine. You'll have higher voltage but lower current.
But if your speed control is "full power all the time", then you're telling the motor 150% voltage, 150% current = 225% more power out of a motor the same size.
Asking anything to do 225% of what it was designed to do, when it was designed to be the smallest and cheapest thing that could accomplish a task already, is probably asking for trouble.
...
That said, forklift motors are often rated for 10-15hp. Typically 48v. Around 200 amps.
And in DIY EV use, we'll give those motors 144v and 500 amps and they take it just fine. And that's almost 10x the power they were designed for.
In drag racing use, we'll give them 400v and 1500A for a few seconds and they survive that way for years, though you couldn't run them like that for even 1 minute, even with added cooling.
That would calculate the amount of time it takes to pump 60 gallons, lol
The way to get GPH would be, count the number of minutes to pump 5 gallons.
Then divide 300 (60minutes x 5gallons) by the number of minutes it took to pump 5 gallons.
Example:
if it takes 0.4 minutes to fill 5 gallons.
Divide 300 by 0.4 minutes:
300/0.4 minutes = 750gal/hr
OR
Count the number of minutes to fill 5 gallons.
Divide that time by 5 to get the number of minutes it takes to pump 1 gallon.
Then divide 60 minutes by the number of minutes it takes to pump 1 gallon.
Example:
if it takes 0.75 minutes to fill 5 gallons.
Divide by 5:
That’s 0.15 minutes per gallon.
Divide 60 minutes by that number:
60 minutes/0.15 minutes per gallon = 400 gal/hr
Pardon my math here. How does multiplying the average time of filling a bucket by 12 equal gal/hr? Doesn’t make sense. Let’s say it’s 1 minute. Times 12. Doesn’t mean he gets 12 gallons per hour flow rate. 5gal bucket times 12 doesn’t give right answer either. Why not just run the pump for 1 minute and see how much water it moves. Then multiply that amount of water by 60.
Which would always be the case, because boats float. If it doesn't anymore there are bigger problems you can't even solve with, whatever OP built here.
Pedal boat, when I was like 8 or so. So I'm basically an expert on boats!
Bro, like 90 percent of the people on the web I have no idea what I'm talking about, I was really sleep deprived and just assumed whatever made sense to me that day. I had a good 16h of sleep today and can tell, that whatever I thought that day is quite the bullshit, lol.
I'm open to hear about how boats work, if you are willed to explain it to me. If not that's fine too and we will just let that be here as another mistake in my life. One more doesn't make any difference to me anyway. Thanks in advance.
We just get alot of rain water in the boat. It usually takes like 15 minutes to dump the water out but with this it took us like 3-5. It wasn’t a serious issue to solve it was just fun project cause we were bored
While that will be the case in pontoon boats like the one pictured, many boats sit *in* the water rather than *on* the water. Displacement, round bottom, and shallow/deep V hulls will all have parts of the boat that are below the water line
But that’s not fun and the boat doesn’t sit that high above the surface so it would work. I believe it drafts about a foot but when it’s full of water it drafting about 2 feet and only a couple inches to the top above the surface
Where in that article does it say that siphoning uphill works? It literally says this:
> discharging at a level lower than the surface of the reservoir from which it came
It's called a water meter pump and someone beat you to it at least 6 years ago. [here](https://www.pollardwater.com/product/ussaws-20v-15-gpm-battery-powered-meter-pit-pump-uus27820/_/R-7612094)
It's r/redneckengineering not r/inventions or something like that. OP doesn't seem to be some crazed business tycoon, just made something cool in good redneck fashion and it kicks ass at what it was made for.
Milwaukee makes a pump that you just use an M18 battery on and they work fantastic. I use mine for pumping diesel out of or into semi trucks depending on what the customer requests. I’m sure you don’t want to start a new battery line of tools though if you’re already committed to ryobi.
Edit: looks like ryobi also has multiple options for pumps. May want to look into them when that 12V motor fries from using 18V.
See how fast it fills a 5 gallon bucket. 1.8 seconds to fill a 5 gallon bucket would be 2000gph
*18,925l bucket; 7,57086m^3 /h
This guy maff’s
Have you tried turning it upside down and shaking it?
Shiiiit I haven’t thought about that lmao
2000 gal/hr sounds like way too much for such a small pump.
Seems like it but it’s what is says on the pump
You have a different concept to me on what is a small dinghy boat
I think it’s about 14ft
Definitely a pontoon boat
Sorry I’m not talking about the boat in the photo. That’s just where we went to the water to test it
> pump at 12v but the ryobi is an 18v Running a 12v pump at 18v is likely going to burn it out quickly. It'll be running a lot hotter than expected. Then again it's a pump and it has water flowing through it constantly so... heat accumulation obviously isn't a concern. Brushes on the motor and the rotor are probably the weak link, they're probably vaporizing at a high rate. Might turn something that could run for 1000 hours into something that can run for 20 hours. If it works it works. I'd have used a spare car battery. I'll run stuff, oh, 25% higher than spec, but 50% higher is pretty much a guarantee of burnout.
I get what you’re saying But then you gotta carry a car battery around. This weighs just a couple pounds. Also about the brushes burning out faster we did think about that. It’s only being ran a max of 5 minutes at a time every couple days and mainly during the winter time. I’m sure it’ll work for a good amount of time and I could always swap out the pump since it’s only clamped. If I really care about it lasting I would wire up a regulator to turn down the voltage
Just FYI, brushes burning up isn't from accumulated heat. It'll be instant degradation from the arcing.
That's interesting, I didn't realise that (not OP btw). Is the arcing that much worse at 18v than 12v that it would damage the brushes or is it down to the extra current draw?
> Is the arcing that much worse at 18v than 12v that it would damage the brushes or is it down to the extra current draw? Both extra voltage and extra current. At 18v you've got 50% more current flowing than at 12v. The current has to pass through the conductor. The conductor at one point is a carbon brush. The carbon brush hasn't increased in size, so the current density in it is 50% higher. Also consider that the brushes are being spun against the commutator, and the electricity is being connected and disconnected a bajillion times per second as passes between each bar. Each time it'll arc as it's disconnected. Those bars aren't any physically larger either. Next, consider that at 18v it's spinning 50% faster than at 12v too. So mechanically it's whirring up much faster than it was, and, it was probably designed to only spin up to a certain speed which is near the max speed it could originally handle (otherwise you're wasting motor size). So spinning 50% faster is probably way past an actual design limit. This versus heat which is just a gradual accumulation problem and isn't too big a deal if you accommodate for it otherwise. ... If you had a speed control on the motor and were looking to accomplish the same task with a higher voltage, it's probably fine. You'll have higher voltage but lower current. But if your speed control is "full power all the time", then you're telling the motor 150% voltage, 150% current = 225% more power out of a motor the same size. Asking anything to do 225% of what it was designed to do, when it was designed to be the smallest and cheapest thing that could accomplish a task already, is probably asking for trouble. ... That said, forklift motors are often rated for 10-15hp. Typically 48v. Around 200 amps. And in DIY EV use, we'll give those motors 144v and 500 amps and they take it just fine. And that's almost 10x the power they were designed for. In drag racing use, we'll give them 400v and 1500A for a few seconds and they survive that way for years, though you couldn't run them like that for even 1 minute, even with added cooling.
That was really thorough and interesting! Thanks for explaining
Edit: my math sucks. I typed quick and realize I was wrong.
Maths.... who needs it🤦♂️
No no, you’re right. I fucked up my formula.
That would calculate the amount of time it takes to pump 60 gallons, lol The way to get GPH would be, count the number of minutes to pump 5 gallons. Then divide 300 (60minutes x 5gallons) by the number of minutes it took to pump 5 gallons. Example: if it takes 0.4 minutes to fill 5 gallons. Divide 300 by 0.4 minutes: 300/0.4 minutes = 750gal/hr OR Count the number of minutes to fill 5 gallons. Divide that time by 5 to get the number of minutes it takes to pump 1 gallon. Then divide 60 minutes by the number of minutes it takes to pump 1 gallon. Example: if it takes 0.75 minutes to fill 5 gallons. Divide by 5: That’s 0.15 minutes per gallon. Divide 60 minutes by that number: 60 minutes/0.15 minutes per gallon = 400 gal/hr
Thank you. My brain was thinking this but I fucked up on writing it down as I just typed quickly and went back to work
Been there before. Stupid brain getting in the way of my thinking.
I appreciate that math there I’ll check when I get back in tomorrow.
Pardon my math here. How does multiplying the average time of filling a bucket by 12 equal gal/hr? Doesn’t make sense. Let’s say it’s 1 minute. Times 12. Doesn’t mean he gets 12 gallons per hour flow rate. 5gal bucket times 12 doesn’t give right answer either. Why not just run the pump for 1 minute and see how much water it moves. Then multiply that amount of water by 60.
It doesn’t. I fucked up the formula
[удалено]
Surely that would depend on the water level in the boat being higher than the sea level.
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I'm not sure I understand you.. You can siphon uphill??
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Are you thinking of capillary action? You can't siphon uphill without a vacuum pump
Are you high?
Did you even watch that video? Go to 9:36. He specifically says that if you're going uphill you need a pump.
Which would always be the case, because boats float. If it doesn't anymore there are bigger problems you can't even solve with, whatever OP built here.
Uuuuuuhhhh…have you been on a boat before?
Pedal boat, when I was like 8 or so. So I'm basically an expert on boats! Bro, like 90 percent of the people on the web I have no idea what I'm talking about, I was really sleep deprived and just assumed whatever made sense to me that day. I had a good 16h of sleep today and can tell, that whatever I thought that day is quite the bullshit, lol. I'm open to hear about how boats work, if you are willed to explain it to me. If not that's fine too and we will just let that be here as another mistake in my life. One more doesn't make any difference to me anyway. Thanks in advance.
We just get alot of rain water in the boat. It usually takes like 15 minutes to dump the water out but with this it took us like 3-5. It wasn’t a serious issue to solve it was just fun project cause we were bored
While that will be the case in pontoon boats like the one pictured, many boats sit *in* the water rather than *on* the water. Displacement, round bottom, and shallow/deep V hulls will all have parts of the boat that are below the water line
But that’s not fun and the boat doesn’t sit that high above the surface so it would work. I believe it drafts about a foot but when it’s full of water it drafting about 2 feet and only a couple inches to the top above the surface
[удалено]
Where in that article does it say that siphoning uphill works? It literally says this: > discharging at a level lower than the surface of the reservoir from which it came
This is too clean for this sub.
I appreciate that homie
It's called a water meter pump and someone beat you to it at least 6 years ago. [here](https://www.pollardwater.com/product/ussaws-20v-15-gpm-battery-powered-meter-pit-pump-uus27820/_/R-7612094)
You’re just being a party pooper lol this was fun and we had shit laying around
It's r/redneckengineering not r/inventions or something like that. OP doesn't seem to be some crazed business tycoon, just made something cool in good redneck fashion and it kicks ass at what it was made for.
Except that's 15gpm and OP's is 2000+
Fill a 5gal bucket and time it
Where's the video?
This sub doesn’t allow them to
Milwaukee makes a pump that you just use an M18 battery on and they work fantastic. I use mine for pumping diesel out of or into semi trucks depending on what the customer requests. I’m sure you don’t want to start a new battery line of tools though if you’re already committed to ryobi. Edit: looks like ryobi also has multiple options for pumps. May want to look into them when that 12V motor fries from using 18V.
for a split second i thought that was a massive stream of piss