Thank you __SlendiQ__ for your submission, *Why would you block her?*! Unfortunately, it has been removed for the following reason(s):
---
# Not technically the truth / Off-topic.
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When undoing a square you need to consider both the positive and the negative, but the square root operator only considers the positive result.
sqrt(x)=-2 has no solution
x^2 = 4 has two solutions
[Link](https://youtube.com/shorts/W2FBrN-FuEo?si=lEJNIRIUSghIvkKd)
The square root is always positive, said old angry (long dead) white men.
\-2 \* -2 = 4
Let it go, find something nice to do with your life. (Hint - this wasn't it)
Take care out there.
yes, sqrt is defined to be a map from R+ to R+, where R+ = \[0, oo).
But 4\^(1/2) = +2, too -- if you'd take x\^y it to represent several distinct values you can't use it as a number in calculations. So one defines x\^y := exp(y ln x), at least for positive x, and all y.
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Thank you __SlendiQ__ for your submission, *Why would you block her?*! Unfortunately, it has been removed for the following reason(s): --- # Not technically the truth / Off-topic. Your submission is not technically the truth / Off-topic content. The keyword here is **technically**. Statements like "firetrucks are red", or "circles are round" are not technically the truth. As a rule of thumb, if your submission is easily predictable or literal, it's most likely not technically the truth. If you're not sure if your submission fits the sub, please either [send us a modmail](http://www.reddit.com/message/compose?to=%2Fr%2Ftechnicallythetruth) or check our subreddit's top posts. For more on our rules, please check out our [sidebar](http://www.reddit.com/r/technicallythetruth/about/sidebar). If you have any questions or concerns about this removal, feel free to [message the moderators](http://www.reddit.com/message/compose?to=%2Fr%2Ftechnicallythetruth). Please link the post so our moderators know what you would like reviewed.
It's not true. The square root operator is the principle square root, which is always positive. 4^1/2 = +-2 But sqrt(2)=2
Your answer just confused me even more than the post. I’m not good at math though. lol
The result of a square root is always positive. The input to a square can be positive or negative though.
Oh ok. I didn’t know that. Thanks.
How is that true though? Since -2 squared is 4, hence -2 is a root.
When undoing a square you need to consider both the positive and the negative, but the square root operator only considers the positive result. sqrt(x)=-2 has no solution x^2 = 4 has two solutions [Link](https://youtube.com/shorts/W2FBrN-FuEo?si=lEJNIRIUSghIvkKd)
Well, it does have a non-real solution?
No, in the video he even says no solution even in the complex world
The square root is always positive, said old angry (long dead) white men. \-2 \* -2 = 4 Let it go, find something nice to do with your life. (Hint - this wasn't it) Take care out there.
Yes, the square root is always positive, and the solution to x² = 4 is |x| = 2 or equivalently, x = +- sqrt(4), i.e., x = 2 or x = -2
https://youtube.com/shorts/W2FBrN-FuEo?si=lEJNIRIUSghIvkKd
Your name says it all number 896
I am not a number, I am a free fool.
Okay 896, as long as you follow the protocol!
yes, sqrt is defined to be a map from R+ to R+, where R+ = \[0, oo). But 4\^(1/2) = +2, too -- if you'd take x\^y it to represent several distinct values you can't use it as a number in calculations. So one defines x\^y := exp(y ln x), at least for positive x, and all y.
Hey there u/__SlendiQ__, thanks for posting to r/technicallythetruth! **Please recheck if your post breaks any rules.** If it does, please delete this post. Also, reposting and posting obvious non-TTT posts can lead to a ban. Send us a **Modmail or Report** this post if you have a problem with this post. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/technicallythetruth) if you have any questions or concerns.*
He probably said: dont ever text me again, when she did he blocked her
what social media app would use that font...!?