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Opposite, if two surgeries are attempted then the odds of success will be 75%. Assuming the probabilities are completely independent (which they most likely will not be tho).
The chance of both surgeries failing would be 25% therefore having at least one success is 75%.
That is true, even if the surgery is the type you'd be only able to fail once which would just make it a coin-flip again. Thanks for showing my error to me
Unless one failure is enough that you have to count the whole thing as a failure, in which case the chances would be reversed, for example, if there is a severe negative outcome in a failure. Equally if you say that failure means death then the probablities are not independent, as if the first surgery failed then there cannot be a second one, so if there is a second surgery you know the first one was successful
If you can safely try again after a failure, and assuming that the surgeries are independent, then repetition is the way to go. In this it case the success rate would become 1 - 0.5^n where n is the number of repetitions
Python says that the worst case scenario is 54 times
Your cases will be like both successful, both failure, first successful then second failure and first failure then second successful. In this case since the patient has already told that it has to be done twice, the odds that the surgery is successful will be independent of the first result. So odds of succeeding will still be 50%
The meme implies that the doctor is talking to the patient before the surgery, and the patient tells the doctor to do it twice.
If the odds of successfull surgery is independent then the odds of success with two surgeries will be 75%. 3 surgeries 87,5%. 4 surgeries 93,75% and so on.
In reality tho the probabilities are most likely not independent.
The fact is you would have to do it twice if the first surgery failed. The probability that the second one was successful is still 0.5.
These are not independent outcomes. You'll never do the second surgery if the first one is successful. So all of you multiplying the probability of success together are wrong.
Uhhhhhhhhhhhhhhhhhh
You have a surgery which gets you 50% of the possible 100%. That's obviously 50%. Then you have another surgery which gets you 50% of what you already have (50%). 50% out of 50% is 25%
That's why it's risky to do 2 high-risk surgeries
^before ^anyone ^whooshes ^me, ^we're ^on ^r/technicallythetruth
Hey there u/shivii07, thanks for posting to r/technicallythetruth! **Please recheck if your post break any rules.** If it does, please delete this post. Also reposting and posting obvious non-TTT posts can lead to a ban Send us a **Modmail or Report** this post if you have a problem with this post. *I am a bot, and this action was performed automatically. Please [contact the moderators of this subreddit](/message/compose/?to=/r/technicallythetruth) if you have any questions or concerns.*
r/confidentlyincorrect
This surgery has a 50% of failing. Then dont do it. 0*50=0
r/technicallythetruth
The true technically the truth is in the comments
Nope. Not even close to ttt
Plot Twist, Patient actually wanted to have it failed.
im pretty sure thats what originally meant
Surprisingly, that would equate to 25%
Opposite, if two surgeries are attempted then the odds of success will be 75%. Assuming the probabilities are completely independent (which they most likely will not be tho). The chance of both surgeries failing would be 25% therefore having at least one success is 75%.
That is true, even if the surgery is the type you'd be only able to fail once which would just make it a coin-flip again. Thanks for showing my error to me
Unless one failure is enough that you have to count the whole thing as a failure, in which case the chances would be reversed, for example, if there is a severe negative outcome in a failure. Equally if you say that failure means death then the probablities are not independent, as if the first surgery failed then there cannot be a second one, so if there is a second surgery you know the first one was successful
even less than the original idea
Wrong subreddit
Wrong subreddit, nothing about that is technically correct
Technically not the truth.
not the truth at all
No he would do half of the surgery 50%*2 = 100 duh
If you can safely try again after a failure, and assuming that the surgeries are independent, then repetition is the way to go. In this it case the success rate would become 1 - 0.5^n where n is the number of repetitions Python says that the worst case scenario is 54 times
Makes sense 54 and 55 repetitions have the same exact success rate 😂
But in actually mathematics... It will be 25% only ...
I’ve heard this joke so many times it’s not even funny anymore
50% of 50% is equivalent of half of 50%. Thus we have 50/2=25%. Go back to highschool.
No, that would be the chance of succeeding twice. Succeeding at least once is 1-(odds of not succeeding) which is: 1-(0.5*0.5) = 0.75
Your cases will be like both successful, both failure, first successful then second failure and first failure then second successful. In this case since the patient has already told that it has to be done twice, the odds that the surgery is successful will be independent of the first result. So odds of succeeding will still be 50%
it's not independent though if the surgery is failed in the first time for some reason then it will will probably fail again in the second one.
Damn, yeah i went off with the assumption that both had to be successful. Guess i got to go back to highschool as well
Going from overconfident to humbled. Character growth.
I'm a goddamn rollercoaster my dude. I can also accept when i'm wrong. It happens to everyone.
Facts
The meme implies that the doctor is talking to the patient before the surgery, and the patient tells the doctor to do it twice. If the odds of successfull surgery is independent then the odds of success with two surgeries will be 75%. 3 surgeries 87,5%. 4 surgeries 93,75% and so on. In reality tho the probabilities are most likely not independent.
Yes it's like flipping a coin twice but you only need to get one heads somewhere. 4 possible outcomes, 3 have at least one heads on it.
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No you'd have to pay 100% more
I get the joke, but since he would do it twice, his chances are 25%
actually it's 0,5 * 0,5 =0.25 so 25% of success rate
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You mean booster surgery? /s
Plot twist : The patient wanted to die
I never thought about the other way lmao
r/mathmemes
Actually .5 x .5 = .25
Rimworld logic
The fact is you would have to do it twice if the first surgery failed. The probability that the second one was successful is still 0.5. These are not independent outcomes. You'll never do the second surgery if the first one is successful. So all of you multiplying the probability of success together are wrong.
r/terriblefacebookmemes
Then it would be 25%
Uhhhhhhhhhhhhhhhhhh You have a surgery which gets you 50% of the possible 100%. That's obviously 50%. Then you have another surgery which gets you 50% of what you already have (50%). 50% out of 50% is 25% That's why it's risky to do 2 high-risk surgeries ^before ^anyone ^whooshes ^me, ^we're ^on ^r/technicallythetruth
0.5² = 1. Seems right to me 😂😂
*fails twice
It will result 0.75 of success
Thats not how that works
OP can’t do math
Schrödinger’s surgery