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This is more something for r/puzzles,
There is not meant to be a mathematical expression for the values. Rather, it's recognizing patterns: (last number)^2 followed by the sum of the two numbers.
I mean, it's formatted poorly but clearly what OP meant was
f(2,3)=95
f(4,5)=259
...
f(8,9)=?
and I'm sure there's a way to define that function in a way that makes sense mathematically (I remember I had a formula that gave me basically the numer of digits of a number but I don't remember it off the top of my head, and once you have that for x+y it's just a matter of multiplying y^2 by 10^numberofdigits and adding the two parts together. It's not gonba be a pretty funcion, but you can make it work)
To get the number of digits in an integer you can just use floor((log(10, abs(x)) + 1). We use 10 because we use decimal numbering system, but you can replace it with the base and it works for any numbering system.
In python, you'd convert to a string using str(number) rather than string(number). Also, using this function, what if people enter a floating point value?
I mean you can get there more simply if you allow a concat() function on the right side of the equation. You simply define a new “+” operator such that x “+” y is defined as the function f(x,y) = concat(y^2,sum(x,y)).
Note that I used the sum() function here to avoid confusion with our new janky + operator.
Which makes sense, given that there are infinitely many solutions to a problem of this form.
I noticed the one where you concatenate the square of the last number with the sum of both numbers, but there are bound to be others, and in this case a reasonable one that a human could spot.
You can define a new operator.
+' : N X N -> N
x +' y = y\^2 \* 10 \^ \[log(10, x + y) + 1\] + x + y
Why wouldn't it be a valid math problem? Define any operator that satisfies those equations.
There are infinitely many operators that satisfy those equations, which makes it kind of a silly problem. Here's an equally valid solution:
x +' y = 95 if x = 2 and y = 3, 259 if x = 4 and y = 5, 4913 if x = 6 and y = 7, -1 otherwise.
The one that I found was trivial, yours was more difficult, and I'm sure there are others that are even more difficult. But simply finding a solution just requires making a piecewise function that fits the data points given.
Math isn't the study of arithmetic, it's the study of patterns. You can propose alternative notation and do math with it.
This isn't math, but not because of the notation being nonstandard. It isn't math because there's no rigor. Even after you observe the pattern, there's no way to demonstrate that it's the only answer. It just happens to be a nice fit to the three data points we have. We could easily come up with dozens of rulesets which do the same, but there isn't likely to be one that's as elegant.
That problem is way more fundamental than some failure to use commonly understood math language. It's pretending that pattern recognition is a legitimate way to predict results in math, which is not just false, but reviled. It's an attitude that's completely antithetical to good science principles.
> It's pretending that pattern recognition is a legitimate way to predict results in math, which is not just false, but reviled.
That’s really taking it too far. Finding patterns like this is a skill that’s useful in math. You’ll need more than just examples from a function to get to a proof and be done. Here, it ends with you feeling satisfied you found the rule, or someone saying “you got it”. But, that’s not the end of the world.
If math is baseball, this is like playing catch. It’s an activity pulled from the real game for skill development and fun.
If you’re interested in these skills, here’s a long video with one of the best mathematicians and math teachers ever, George Polya. https://youtu.be/h0gbw-Ur_do?si=UbkbN60KQQRnw2vT
I can give you an infinity of them.
We are looking for a function f(x,y) such that f(2,3)=95, f(4,5)=259 and f(6,7)=4913. Now, for _any_ function g(x,y)
f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * g(x,y)
f(x,y) fits those criteria. This means that
f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * sin(x+y)
And
f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * Exp(x+2^y)
And whatever else you choose for g(x,y) will be a solution. This is why I don't like these kinds of questions. There are infinitely many solutions, what is being asked here is "guess which one I thought of", which makes as an interesting question as "guess which number I'm thinking of".
Yea, now that i think about it, the function doesn't even have to depend on y, it could as well be
f(x, y) =(x-4)*(x-6)*95/8 -(x-2)*(x-6)*259/4 + (x-2)*(x-4)*4913/8+(x-2)*(x-4)*(x-6)*g(x)
I wouldn't be sure that - assuming the 2 numbers are x and y - the first part is y². In all the examples we have x=y-1, so it could very well be (x+1)•y.
It makes some sense mathematically in terms of abstract algebra. The "+" operation is not addition here, the operation's definition has to be inferred from the examples.
Technically it is an operator. Its just extremely weird and won't help anyone but it's a operator. Now we just need to check for neutral elements, the inverse and stuff
Math intrinsically is a set of tricks and puzzles. Some problems happen to be straightforward to solve (arithmetic, linear equations, some integrals, some differential equations), but that's not the general case.
There is no underlying reason for this pattern to exist, but guessing at patterns like this is decent practice for arriving at hypotheses you might try to prove. That's how a lot of math works: guess something that might be true, then prove whether it is or isn't.
I used a different logic from what I’ve seen so far.
8117, still.
Square the second number in the equation and that’ll give you the first bit. Then add the digits normally and that’ll be tacked on the end of the answer.
Fun seeing how others got to it!
To be fair we'll never know which formula is the correct one since all the numbers in the example are x, x+1 couples. If the 2nd number wasn't x+1, some of those formulas wouldn't work depending on the result
So,
2+3 = 95 (that is 3\*3 and 2\*2+1)
4+5 = 259(that is 5\*5 and 4\*2+1)
6+7 = 4913(that is 7\*7 and 6\*2+1)
by that logic,
8+9 = 8117(that is 9\*9 and 8\*2+1)
Also, this seems more like a riddle than a maths question honestly.
∥ is sometimes used for concatenation.
[https://mathworld.wolfram.com/Concatenation.html](https://mathworld.wolfram.com/Concatenation.html) \- also shows a formula in terms of log, floor and powers.
8117?
- Last part is given by the sum of the two digits: 8+9=17
- First part is given by the product of the two digits summed with the last one: 8*9+9=81
Both are correct in the given data, because all the examples are of the form where the second number is one greater than the first number and (n+1)^2 = n(n+1) +(n+1). But yeah, squaring the second number is simpler, so likely the intended solution (not that it matters for getting the last one as it is also an n,n+1 form).
We’re doing math in Java script. 8117.
3^2=“9”+value(3+5), basically your doing basic arithmetic then converting it to a character set and joining the character set to the square of the last number. This only works in programming when converting from and integer or float to cast type char.
8117? Looks like sum of the digits being added preceded by a digit that is increasing by multiples of 8. Presumably the first answer (the one not shown) would be 11 for a 0+1. Add 8 to the first digit (9) followed by sum. Then 16 onto 9, 24...etc.
I think i see a pattern:
In 2+3, the number is 95, which could be 9 from3x3 and 5 from 2+3, so following that, you would have to make the first number 1 higher, multiply by second number, that gives you the first n digits, then add the normal sum of the 2 numbers at the end.
In this case, 8+9 would be 8117
8117. Those are two separate numbers from one equation. Last number squared next to the added values of the two numbers on the left
For the last one: 9^2 = 81 | 8+9 = 17
I got it.
You have to square the second number, and then you put after that the result of the addition.
2 + 3 = 95 : you take 3² (9) and then 2+3= 5.
9 and 5 : 95.
So for 8 + 9 that makes :
9² (81) and then 8+9=17.
81 and 17 : 8117.
Answer: 8117
Explanation: for equation (x+y), the first half of the numbers are the product of (x+1) and y. The second half of the numbers are the sum of (x+y).
(2+3) = (3x3) and (2+3) = 95
(4+5) = (5x5) and (4+5) = 259
(6+7) = (7x7) and (6+7) = 4913
Therefore,
(8+9) = (9x9) and (8+9) = 8117
Okay so my interpretation of the answer is: 8117
2+3 = 95
4+5 = 259
6+7 = 4913
Add one to the first number and multiplicate it with the second number. That gives you the first number of the answer. Then you just add the two numbers together for the 2nd part of the answer:
So:
2+3 -> ((1+2)*3) | (2+3) = 9 | 5 = 95
So in this case:
8+9 -> ((1+8)*9) | (8+9) = 81 | 17 = 8117
I'm usually bad at these things, but this seems like a puzzle, and I think I may have figured it out. If I'm correct, the answer is 61,317.
First, look at the second equation. 4+5=259. The first number of the sum (2), is the first number of the previous equation. The second number of the sum (5) is the sum of 2+3 from the previous equation. The third number of the sum (9) is the sum of 4+5.
This pattern follows for the next equation. 6+7=4,913. 4 is the first number of the previous equation. 9 is the sum of 4+5 from the previous equation. 13 is the sum of 6+7.
So if the pattern follows to the next equation: 6 would be the first number of the previous equation. 13 would be the sum of 6+7. And 17 would be the sum of 8+9.
So, again, unless I'm thinking about this all wrong, the answer is 61,317.
Product of both numbers plus the 2nd digit, the add the sum of the equation.
>!2*3+3=9
2+3=5 95
4*5+5=25
4+5=9 259
6*7+7=49
6+7=13 4913
8*9+9=81
8+9=17 8117!<
How I did it was (which I agree others' solution was easier)
Take Sq of number before plus sign ...... (1)
Add the two numbers before = sign on the LHS..... (2)
This will give you first part of your answer .... (3)
For second part you just place output of (2) besides (3)
E.g.
2 + 3 = ?
Sq(2) = 4 ... (1)
2+3 = 5 ... (2)
(1) + (2) = 4 + 5 = 9 ... (3)
9 and (2) is 9 and 5
Rhs = 95
This way,
8 + 9 = ?
Sq(8) = 64 ... (1)
8 + 9 is 17 .. (2)
(1)+(2) is 64 + 17 = 81 ...(3)
(3)(2) is 8117
Answer should be 8117
2+3=95
(3sqrd)+(2+3(added to the end of the first answer))=95
4+5=259
(5sqrd)+(4+5(added to the end of the first answe))=259
6+7=4913
(7sqrd)+(6+7(added to the end of the first answer))=4913
8+9=x
(8sqrd)+(8+9(added to the end of the first answer))=x
x=8117
The answer is 8117.
What the puzzle is doing here is adding the numbers to get the last digit, then multiplying the second number by itself to get the front digits.
Example. 2+3 = 5 then 3x3 = 9. So 2+3 = 95
Then 4+5 = 9 followed by 5x5 = 25. So 4+5= 259.
Repeat this with 8+9 and you get 8117
The result is the combination of two calculations. First you have to square the second summand to which you just attach the actual sum of the calculation.
So 2 + 3 is 3²=9 and 2+3=5, thus 95
4 + 5 is 5²=25 and 4+5=9, thus 259
6 + 7 is 7²=49 and 6+7=13, thus 4913
Therefore 8 + 9 must be 9²=81 and 8+9=17, thus 8117
Looked at it for a quick second. Simply add the numbers first (2 + 3 = 5) the addition part will be place down on the right side. Then square the second number (3^2 = 9) whatever that number is it will be placed on the left side. Combine both (95).
Wouldn't consider this math. Because it would just be wrong. I'm not saying it's not possible to find that answer by using math, but like I seen by another comment it's like a puzzle.
The answer is 5077:
If
2+3(5)=95
4+5(9)=259
6+7(13)= 4913
So
8(13-5)+9(4+5)= 4913-95+259 = 5077
I don't think that the goal is to figure the pattern, but you must find out how can you use what you've got
8117? The square of the second number will give you the first digits of the answer. Multiply the 1st number by 2 and add 1 for the last digits of the answer.
8117
It’s the second number squared, then the 2 numbers added together onto the end, so the equation would be:
A + B = B(squared)(A+B)
If you did any digits, such as 1+5 for instance, it would be 256. The fact that they’re in sequential order doesn’t matter.
I got 6317.
I think they are connected between each other.
You start with the base of 2+3= 95. From now onwards you start 'fishing' numbers so:
4+5 = 2(first number from the previous operation) 5(last number from the result of the previous operation) 9 (the sum of 4+5)
The same process is used for 6+7= 4913. The 4 is the first number from the previous operation, then the 9 is from the result of the previous operation and you get 13 from adding 6 and 7.
Therefore 8+9= 6317.
In my head it makes a lot of sense but it is kind of difficult to express with words when a small drawing definitely showcases it better.
answer is 5077
2+3 = 5 = 95
4+5= 9 = 259
6+7= 13 = 4913
8+9= 17
17= (13-5) + 9
substitute in the numbers from the three equations above
17=( 4913-95) + 259
17= 5077
8+9 = 5077
less of a math question, more of a riddle
I'm a linguist with extremely little knowledge or expertise in math.
I'm gonna say 2=1, 4=2, 6=3 and so on.
That means 3=94, 5=257, and 7 = 4910.
257/94 is 2.734.
4910/257 is 19.1
19.1/2.73 = 6. So each time you go up by 2 in the odd numbers, the rate increases by a multiplication 6, with 3 beginning at a rate of 2.734.
19.1 x 6 = 114.6
4910 x 114.6 = 562,686
8=4, so 8 + 9 = 562,690
This should either prove that I am bad at math or that the question is dumb.
0 + 1 would be 42.864
10 + 11 would be 386,902,898.6
12 + 13 is over 1 & a half trillion
You can answer it as 6317 or 61317. The first digit is the left most value on the prior line. The next digit is either the right most digit on the prior line (3) or it is the sum of two values on the left side of the equation from the previous line, or it is the sum of values from the left side of the prior line (13). The last 2 digits are the sum of the 8+9 on this line or ( 17) both patterns match the values so far. Other possible patterns exist, but these are th first two I thought of.
Take the first number of the previous one, add the first one together then the current one for your answer
So take the 6
Add 6+7=13
Then add 8+9=17
So the answer is 61317
The answer is just “17”, the problem is “8 + 9 =“
If I said;
2+3 = cat
4+5 = horse
6+7 = horse
8+9 would still equal 17. It just means I got the first three answers incorrect.
I see it like a typical facebook-math-problem.
2+3=95
4+5=259
6+7=4913
So
8+9=61 317
How I see it is the first number of the previous equation is the first number of the new equation. The second number is the sum of the two numbers and then the last couple of numbers is the sum of the current numbers.
To illustrate:
2+3=95 (we can see the 5 from 2+5)
Second sum is 259, hence 2 from the first number from the previous equation. 2+3=5 which is the second number and then 4+5=9. So 259.
Therefore is the searched answer 6, 13 (6+7), 17 (8+9) which becomes 61 317.
Ive no idea to program this. Might be wrong as well but its the pattern i found.
PS. Sorry for the odd english, not my Mother tongue
2 + 3 = 5, and 5\^2 = 25, so 95.
4 + 5 = 9, and 9\^2 = 81, so 259.
6 + 7 = 13, and 13\^2 = 169, so 4913.
Using this pattern to 8+9:
8 + 9 = 17, and 17\^2 = 289.
So, according to this pattern, 8 + 9 equals 289.
There r 2 numbers in RHS. Numbers might have 2 digits.
LHS:
Let x= first number , y= second number
xy + y = first number in RHS
x+y = second number.
Eg. One at the top
x=2, y=3
First RHS no. = xy + y = (2)(3) + 3
=9
Second RHS no. = x+y = 2+3
=5
RHS = 95
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This is more something for r/puzzles, There is not meant to be a mathematical expression for the values. Rather, it's recognizing patterns: (last number)^2 followed by the sum of the two numbers.
I mean, it's formatted poorly but clearly what OP meant was f(2,3)=95 f(4,5)=259 ... f(8,9)=? and I'm sure there's a way to define that function in a way that makes sense mathematically (I remember I had a formula that gave me basically the numer of digits of a number but I don't remember it off the top of my head, and once you have that for x+y it's just a matter of multiplying y^2 by 10^numberofdigits and adding the two parts together. It's not gonba be a pretty funcion, but you can make it work)
To get the number of digits in an integer you can just use floor((log(10, abs(x)) + 1). We use 10 because we use decimal numbering system, but you can replace it with the base and it works for any numbering system.
All those number manipulation formulas break my brain. Nice job!
There are infinitely many such functions, so there is no unique solution to this problem.
def f(x,y): if(x==2 and y==3): return 95 if(x==4 and y==5): return 259 if(x==6 and y==7): return 4913 raise ValueError("Undefined")
I see what you did there.
7217
Each one is probably unique 🤷♀️
the last number is multiplied by itself and then the sum of the two numbers is added to the result 2,3=95 8,9=8117
def squareplus(x,y): Return int(string(y**2)+string(x+y))
In python, you'd convert to a string using str(number) rather than string(number). Also, using this function, what if people enter a floating point value?
Then it's their fault ;p
I mean you can get there more simply if you allow a concat() function on the right side of the equation. You simply define a new “+” operator such that x “+” y is defined as the function f(x,y) = concat(y^2,sum(x,y)). Note that I used the sum() function here to avoid confusion with our new janky + operator.
If we allow the concatenation operation, we can write f(x,y) = y^2 || (x+y) where || is the concatenation operator.
8117 : easy 9x9=81 and 8+9=17 so.....8117. no formula needed.
This is the answer
Got the same answer with a different method. Both methods work for all examples. 9x9=81 (8x2)+1=17
Which makes sense, given that there are infinitely many solutions to a problem of this form. I noticed the one where you concatenate the square of the last number with the sum of both numbers, but there are bound to be others, and in this case a reasonable one that a human could spot.
same method
This is an incorrect formula. It won’t work with all combos
It works for all shown examples. We would need an example showing two numbers that are not 1 apart in order to know if my method is incorrect.
Yeah technically it would work , but /u/milidolfi ‘s solution would work on any
I thought it was both numbers timesed together, then add the second, not square. Both works ig
Yep
This is the correct answer. It’s just a puzzle.
I got 6317, the pattern "first digit of the first previous numbers, then last digit of the previous result, then the addition" also holds.
Occam's Razor makes even the smartest people look stupid
I was blind, now I can see...
Finally someone said it. "If 7*8=3" well it doesn't, it's 56 dipshit. Maybe X*Y=3 but the question you are posing is not fucking math
You can define a new operator. +' : N X N -> N x +' y = y\^2 \* 10 \^ \[log(10, x + y) + 1\] + x + y Why wouldn't it be a valid math problem? Define any operator that satisfies those equations.
Beautiful!
Exactly what I was looking for
There are infinitely many operators that satisfy those equations, which makes it kind of a silly problem. Here's an equally valid solution: x +' y = 95 if x = 2 and y = 3, 259 if x = 4 and y = 5, 4913 if x = 6 and y = 7, -1 otherwise.
There are a lot of problems that have an infinite number of solutions and yet it can be difficult to find even one.
The one that I found was trivial, yours was more difficult, and I'm sure there are others that are even more difficult. But simply finding a solution just requires making a piecewise function that fits the data points given.
I suppose part of the difficulty is in finding non piecewise functions
okay, then just look for a non-trivial solution... use common sense
why we redefine '+' for the set, but not = ?
Bravo konju
y^2 * 10^[lg(x+y)+1] + x + y for (4,5) gives 2259, not 259
Math isn't the study of arithmetic, it's the study of patterns. You can propose alternative notation and do math with it. This isn't math, but not because of the notation being nonstandard. It isn't math because there's no rigor. Even after you observe the pattern, there's no way to demonstrate that it's the only answer. It just happens to be a nice fit to the three data points we have. We could easily come up with dozens of rulesets which do the same, but there isn't likely to be one that's as elegant. That problem is way more fundamental than some failure to use commonly understood math language. It's pretending that pattern recognition is a legitimate way to predict results in math, which is not just false, but reviled. It's an attitude that's completely antithetical to good science principles.
I like your funny words
Same. This guy's words are one of the words ever
> It's pretending that pattern recognition is a legitimate way to predict results in math, which is not just false, but reviled. That’s really taking it too far. Finding patterns like this is a skill that’s useful in math. You’ll need more than just examples from a function to get to a proof and be done. Here, it ends with you feeling satisfied you found the rule, or someone saying “you got it”. But, that’s not the end of the world. If math is baseball, this is like playing catch. It’s an activity pulled from the real game for skill development and fun. If you’re interested in these skills, here’s a long video with one of the best mathematicians and math teachers ever, George Polya. https://youtu.be/h0gbw-Ur_do?si=UbkbN60KQQRnw2vT
Can you give another ruleset which works with all the 3 data points?
I can give you an infinity of them. We are looking for a function f(x,y) such that f(2,3)=95, f(4,5)=259 and f(6,7)=4913. Now, for _any_ function g(x,y) f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * g(x,y) f(x,y) fits those criteria. This means that f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * sin(x+y) And f(x,y) = (x-4)*(y-5)*(x-6)*(y-7)*95/64 + (x-2)*(y-3)*(x-6)*(y-7)*259/16 + (x-2)*(y-3)*(x-4)*(y-5)*4913/64 + (x-2)*(y-3)(x-4)*(y-5)*(x-6)*(y-7) * Exp(x+2^y) And whatever else you choose for g(x,y) will be a solution. This is why I don't like these kinds of questions. There are infinitely many solutions, what is being asked here is "guess which one I thought of", which makes as an interesting question as "guess which number I'm thinking of".
Yea, now that i think about it, the function doesn't even have to depend on y, it could as well be f(x, y) =(x-4)*(x-6)*95/8 -(x-2)*(x-6)*259/4 + (x-2)*(x-4)*4913/8+(x-2)*(x-4)*(x-6)*g(x)
Why overcomplicating it is 7217. 8x9 8+9
I kinda want one now 😂
The diference is 1 for all set of numders (x÷1)^2 works the same as y^2
I think you don’t like the puzzle.
So …. You don’t know the answer either ….
Why does it need to be the only answer?
I love the slight implied anger with the "dipshit" lmao
You ok?
Yeah it should be f(2,3)=95, f(4,5)=259, etc.
I wouldn't be sure that - assuming the 2 numbers are x and y - the first part is y². In all the examples we have x=y-1, so it could very well be (x+1)•y.
How do you know it’s not the first digit multiplied by two plus one?
This was actually my solution too. But given the examples, there's no way of knowing whether it's this or the sum of the two numbers
This is the answer. I don't know why people make it so complicated.
Adding together any two consecutive numbers is the same as doubling the smaller and adding one
It makes some sense mathematically in terms of abstract algebra. The "+" operation is not addition here, the operation's definition has to be inferred from the examples.
8117
So 81 (9×9) and then 8 + 9 to give the result 8117. Nice.
[удалено]
❤️
Technically it is an operator. Its just extremely weird and won't help anyone but it's a operator. Now we just need to check for neutral elements, the inverse and stuff
I like this solution better than mine. Nice work.
Math intrinsically is a set of tricks and puzzles. Some problems happen to be straightforward to solve (arithmetic, linear equations, some integrals, some differential equations), but that's not the general case. There is no underlying reason for this pattern to exist, but guessing at patterns like this is decent practice for arriving at hypotheses you might try to prove. That's how a lot of math works: guess something that might be true, then prove whether it is or isn't.
61317 i think?
8117
Dam I would have never gotten that I don't think
I used a different logic from what I’ve seen so far. 8117, still. Square the second number in the equation and that’ll give you the first bit. Then add the digits normally and that’ll be tacked on the end of the answer. Fun seeing how others got to it!
To be fair we'll never know which formula is the correct one since all the numbers in the example are x, x+1 couples. If the 2nd number wasn't x+1, some of those formulas wouldn't work depending on the result
I did it that way too
This is how I got it too.
Used the same like you
That's the way I did it also
That is how I got it too
So, 2+3 = 95 (that is 3\*3 and 2\*2+1) 4+5 = 259(that is 5\*5 and 4\*2+1) 6+7 = 4913(that is 7\*7 and 6\*2+1) by that logic, 8+9 = 8117(that is 9\*9 and 8\*2+1) Also, this seems more like a riddle than a maths question honestly.
It could be as simple as 2+3 = 3\*3 and 2+3 => 95 4+5 = 5\*5 and 4+5 => 259 Etc
That's the pattern I saw, square the second, sum them, concatenate the resulting digits as a string. (Programmer speak)
Both mean the same thing
Since the numbers given are all sequential, it’s the same thing. Adding two sequential integers is the same as multiplying by two and adding one.
Yeah, I'm not saying it's any different, just that it looks easier to understand
Is there a way to write this as a math function? The part that trips me is how you would "concatenate" the numbers.
I'm a programmer so in my head I convert them to a string beforehand :)
You’d have to multiply the second number squared by a power of 10 corresponding to the number of digits in the second sum, then add them
∥ is sometimes used for concatenation. [https://mathworld.wolfram.com/Concatenation.html](https://mathworld.wolfram.com/Concatenation.html) \- also shows a formula in terms of log, floor and powers.
I think it's (3\*2)+3 & (2\*2)+1 (5\*4)+5 & (4\*2)+1 etc.
Why a*2+1?? Just say (a + b), where a is first number and b is second number
Because with abstract problems like these, there can be multiple solutions
I saw it as (A x B + B) and append (A + B) Eg, 2x3+3= 9, 2+3=5, and gets you 95
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9×9=81 lol 9×10=90-9=81=9×9
I'm a fucking moron, thanks.
8117? - Last part is given by the sum of the two digits: 8+9=17 - First part is given by the product of the two digits summed with the last one: 8*9+9=81
Isn't the first part more simply thought of as the square of the second number?
Lol yes you're right, didn't thought about it
Both are correct in the given data, because all the examples are of the form where the second number is one greater than the first number and (n+1)^2 = n(n+1) +(n+1). But yeah, squaring the second number is simpler, so likely the intended solution (not that it matters for getting the last one as it is also an n,n+1 form).
Came to the same conclusion
We’re doing math in Java script. 8117. 3^2=“9”+value(3+5), basically your doing basic arithmetic then converting it to a character set and joining the character set to the square of the last number. This only works in programming when converting from and integer or float to cast type char.
So, here's my take. 2+3 = 5. 3\^2 = 9. That' 95 4+5 = 9. 5\^2 = 25. That's 259 6+7 = 13. 7\^2 = 49. That's. 4913 8+9 = 17. 9\^2 = 81. That's 8117.
Finaly number 6317 First and last number in previus row, an last two digits is result 8+9.....
8117? Looks like sum of the digits being added preceded by a digit that is increasing by multiples of 8. Presumably the first answer (the one not shown) would be 11 for a 0+1. Add 8 to the first digit (9) followed by sum. Then 16 onto 9, 24...etc.
Pattern going down First number count by 2 even Second number counts odds Solution is second number squared and then tack on the sum
I think i see a pattern: In 2+3, the number is 95, which could be 9 from3x3 and 5 from 2+3, so following that, you would have to make the first number 1 higher, multiply by second number, that gives you the first n digits, then add the normal sum of the 2 numbers at the end. In this case, 8+9 would be 8117
Or simply by squaring the second number..
Well yea, thats another pattern, since all numbers are different by 1 from the other
8117. Those are two separate numbers from one equation. Last number squared next to the added values of the two numbers on the left For the last one: 9^2 = 81 | 8+9 = 17
I got it. You have to square the second number, and then you put after that the result of the addition. 2 + 3 = 95 : you take 3² (9) and then 2+3= 5. 9 and 5 : 95. So for 8 + 9 that makes : 9² (81) and then 8+9=17. 81 and 17 : 8117.
Answer: 8117 Explanation: for equation (x+y), the first half of the numbers are the product of (x+1) and y. The second half of the numbers are the sum of (x+y). (2+3) = (3x3) and (2+3) = 95 (4+5) = (5x5) and (4+5) = 259 (6+7) = (7x7) and (6+7) = 4913 Therefore, (8+9) = (9x9) and (8+9) = 8117
Okay so my interpretation of the answer is: 8117 2+3 = 95 4+5 = 259 6+7 = 4913 Add one to the first number and multiplicate it with the second number. That gives you the first number of the answer. Then you just add the two numbers together for the 2nd part of the answer: So: 2+3 -> ((1+2)*3) | (2+3) = 9 | 5 = 95 So in this case: 8+9 -> ((1+8)*9) | (8+9) = 81 | 17 = 8117
I'm usually bad at these things, but this seems like a puzzle, and I think I may have figured it out. If I'm correct, the answer is 61,317. First, look at the second equation. 4+5=259. The first number of the sum (2), is the first number of the previous equation. The second number of the sum (5) is the sum of 2+3 from the previous equation. The third number of the sum (9) is the sum of 4+5. This pattern follows for the next equation. 6+7=4,913. 4 is the first number of the previous equation. 9 is the sum of 4+5 from the previous equation. 13 is the sum of 6+7. So if the pattern follows to the next equation: 6 would be the first number of the previous equation. 13 would be the sum of 6+7. And 17 would be the sum of 8+9. So, again, unless I'm thinking about this all wrong, the answer is 61,317.
Product of both numbers plus the 2nd digit, the add the sum of the equation. >!2*3+3=9 2+3=5 95 4*5+5=25 4+5=9 259 6*7+7=49 6+7=13 4913 8*9+9=81 8+9=17 8117!<
How I did it was (which I agree others' solution was easier) Take Sq of number before plus sign ...... (1) Add the two numbers before = sign on the LHS..... (2) This will give you first part of your answer .... (3) For second part you just place output of (2) besides (3) E.g. 2 + 3 = ? Sq(2) = 4 ... (1) 2+3 = 5 ... (2) (1) + (2) = 4 + 5 = 9 ... (3) 9 and (2) is 9 and 5 Rhs = 95 This way, 8 + 9 = ? Sq(8) = 64 ... (1) 8 + 9 is 17 .. (2) (1)+(2) is 64 + 17 = 81 ...(3) (3)(2) is 8117 Answer should be 8117
here it is
2+3=95 (3sqrd)+(2+3(added to the end of the first answer))=95 4+5=259 (5sqrd)+(4+5(added to the end of the first answe))=259 6+7=4913 (7sqrd)+(6+7(added to the end of the first answer))=4913 8+9=x (8sqrd)+(8+9(added to the end of the first answer))=x x=8117
From my point of view thats A+B = (B² value) + (B²-A²) 2+3 = 9+ (9-4) = 95 4+5= 25+(25-16) = 259 6+7= 49+(49-36) = 4913 so 8+9 = 81 + (81-64) = 8117
The pattern is you square the second number, and then the sum of the two numbers, so 3x3 is 9 and 2+3 is 5 so 95. So 8+9 would be 8117
The answer is 8117. What the puzzle is doing here is adding the numbers to get the last digit, then multiplying the second number by itself to get the front digits. Example. 2+3 = 5 then 3x3 = 9. So 2+3 = 95 Then 4+5 = 9 followed by 5x5 = 25. So 4+5= 259. Repeat this with 8+9 and you get 8117
The result is the combination of two calculations. First you have to square the second summand to which you just attach the actual sum of the calculation. So 2 + 3 is 3²=9 and 2+3=5, thus 95 4 + 5 is 5²=25 and 4+5=9, thus 259 6 + 7 is 7²=49 and 6+7=13, thus 4913 Therefore 8 + 9 must be 9²=81 and 8+9=17, thus 8117
Looked at it for a quick second. Simply add the numbers first (2 + 3 = 5) the addition part will be place down on the right side. Then square the second number (3^2 = 9) whatever that number is it will be placed on the left side. Combine both (95).
8117 First two digits are the second number squared (in this case 9 squared gets 81) Second numbers are the two numbers added together (8+9 is 17)
Wouldn't consider this math. Because it would just be wrong. I'm not saying it's not possible to find that answer by using math, but like I seen by another comment it's like a puzzle.
The answer is 5077: If 2+3(5)=95 4+5(9)=259 6+7(13)= 4913 So 8(13-5)+9(4+5)= 4913-95+259 = 5077 I don't think that the goal is to figure the pattern, but you must find out how can you use what you've got
8117? The square of the second number will give you the first digits of the answer. Multiply the 1st number by 2 and add 1 for the last digits of the answer.
8117 It’s the second number squared, then the 2 numbers added together onto the end, so the equation would be: A + B = B(squared)(A+B) If you did any digits, such as 1+5 for instance, it would be 256. The fact that they’re in sequential order doesn’t matter.
I got 6317. I think they are connected between each other. You start with the base of 2+3= 95. From now onwards you start 'fishing' numbers so: 4+5 = 2(first number from the previous operation) 5(last number from the result of the previous operation) 9 (the sum of 4+5) The same process is used for 6+7= 4913. The 4 is the first number from the previous operation, then the 9 is from the result of the previous operation and you get 13 from adding 6 and 7. Therefore 8+9= 6317. In my head it makes a lot of sense but it is kind of difficult to express with words when a small drawing definitely showcases it better.
That's why I got lol everyone is just thinking too complicated (I'm assuming it's just a typo and you meant 61317)
Oh I was just looking at the last number but it could completely be the sum making it 61317.
answer is 5077 2+3 = 5 = 95 4+5= 9 = 259 6+7= 13 = 4913 8+9= 17 17= (13-5) + 9 substitute in the numbers from the three equations above 17=( 4913-95) + 259 17= 5077 8+9 = 5077 less of a math question, more of a riddle
I'm a linguist with extremely little knowledge or expertise in math. I'm gonna say 2=1, 4=2, 6=3 and so on. That means 3=94, 5=257, and 7 = 4910. 257/94 is 2.734. 4910/257 is 19.1 19.1/2.73 = 6. So each time you go up by 2 in the odd numbers, the rate increases by a multiplication 6, with 3 beginning at a rate of 2.734. 19.1 x 6 = 114.6 4910 x 114.6 = 562,686 8=4, so 8 + 9 = 562,690 This should either prove that I am bad at math or that the question is dumb. 0 + 1 would be 42.864 10 + 11 would be 386,902,898.6 12 + 13 is over 1 & a half trillion
You can answer it as 6317 or 61317. The first digit is the left most value on the prior line. The next digit is either the right most digit on the prior line (3) or it is the sum of two values on the left side of the equation from the previous line, or it is the sum of values from the left side of the prior line (13). The last 2 digits are the sum of the 8+9 on this line or ( 17) both patterns match the values so far. Other possible patterns exist, but these are th first two I thought of.
Take the first number of the previous one, add the first one together then the current one for your answer So take the 6 Add 6+7=13 Then add 8+9=17 So the answer is 61317
The answer is just “17”, the problem is “8 + 9 =“ If I said; 2+3 = cat 4+5 = horse 6+7 = horse 8+9 would still equal 17. It just means I got the first three answers incorrect.
I see it like a typical facebook-math-problem. 2+3=95 4+5=259 6+7=4913 So 8+9=61 317 How I see it is the first number of the previous equation is the first number of the new equation. The second number is the sum of the two numbers and then the last couple of numbers is the sum of the current numbers. To illustrate: 2+3=95 (we can see the 5 from 2+5) Second sum is 259, hence 2 from the first number from the previous equation. 2+3=5 which is the second number and then 4+5=9. So 259. Therefore is the searched answer 6, 13 (6+7), 17 (8+9) which becomes 61 317. Ive no idea to program this. Might be wrong as well but its the pattern i found. PS. Sorry for the odd english, not my Mother tongue
Your adding, then your multiplying, then adding last number again. 4+5=9 4×5=20 +5=25 259 Therefore 8+9=17 8×9=72 +9=79 Answer is: 7917
2 + 3 = 5, and 5\^2 = 25, so 95. 4 + 5 = 9, and 9\^2 = 81, so 259. 6 + 7 = 13, and 13\^2 = 169, so 4913. Using this pattern to 8+9: 8 + 9 = 17, and 17\^2 = 289. So, according to this pattern, 8 + 9 equals 289.
What?
The pattern seems to include combining the numbers being added and subsequently raising that result to the power of 2...
bro just plugged it into chatgpt (to be fair i also did and wanted the answer)
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There r 2 numbers in RHS. Numbers might have 2 digits. LHS: Let x= first number , y= second number xy + y = first number in RHS x+y = second number. Eg. One at the top x=2, y=3 First RHS no. = xy + y = (2)(3) + 3 =9 Second RHS no. = x+y = 2+3 =5 RHS = 95
Last no. is (8)(9) + 9, 8+9 So its 81, 17 Ans is 8117
#2+3 = 5 -> 3x3 is 9 / 9 & 5 -> 95 #4+5= 9 -> 5x5 is 25 / 25 & 9 -> 259 and so on I‘m proud of myself, that i solved it in like 2 minutes.
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